A flexible cable of length 100 m and weight 8 N/m sags 5 m between two supports. If the slope of the cable at the supports is 46 degrees, calculate the total weight of the cable.

Here's a step-by-step solution to the problem:

Given data:

• Length of cable, $L_c = 100$ m
• Sag of the cable, $h = 5$ m
• Weight of the cable per unit length, $w = 8$ N/m
• Slope of the cable at the supports, $\theta = 46^\circ$

First, let's calculate the total weight of the cable:
Total weight $W_{total} = w \times L_c = 8 \text{ N/m} \times 100 \text{ m} = 800 \text{ N}$.

Since the cable is supported between two equal supports, the vertical