Here are the solutions to the problems:
:
a) A metal wire of length 79 cm and diameter 0.31 mm has a resistance of 5.0 Ω. Find the resistivity of the metal wire.
Step 1: Convert given values to SI units.
Length L=79cm=0.79 m
Diameter d=0.31mm=0.31×10−3 m
Resistance R=5.0Ω
Step 2: Calculate the cross-sectional area A of the wire.
The formula for the area of a circle is A=4πd2.
A=4π(0.31×10−3m)2
A=4π(9.61×10−8m2)
A≈7.5498×10−8m2
Step 3: Use the resistance formula R=ρAL to find resistivity ρ.
Rearranging the formula for ρ:
ρ=LR⋅A
Substitute the values:
ρ=0.79m(5.0Ω)×(7.5498×10−8m2)
ρ=0.793.7749×10−7Ω⋅m
ρ≈4.778×10−7Ω⋅m
Rounding to two significant figures:
Resistivityρ=4.8×10−7Ω⋅m
:
b) Determine the resistance of an aluminium cable of length 2.0×104 m and diameter 4.0 mm. The resistivity of aluminium is 3.0×10−8Ω⋅m.
Step 1: Convert given values to SI units.
Length L=2.0×104 m
Diameter d=4.0mm=4.0×10−3 m
Resistivity ρ=3.0×10−8Ω⋅m
Step 2: Calculate the cross-sectional area A of the cable.
A=4πd2
A=4π(4.0×10−3m)2
A=4π(16.0×10−6m2)
A=π×4.0×10−6m2
A≈1.2566×10−5m2
Step 3: Use the resistance formula R=ρAL.
Substitute the values:
R=(3.0×10−8Ω⋅m)×1.2566×10−5m22.0×104m
R=1.2566×10−5m26.0×10−4Ω⋅m2
R≈47.74Ω
Rounding to two significant figures:
ResistanceR=48Ω
:
c) A manganin wire of cross-sectional area 4.0×10−7m2 and resistivity 4.3×10−7Ω⋅m has a resistance of 0.05Ω. Calculate the length of the wire.
Step 1: Identify the given values.
Cross-sectional area A=4.0×10−7m2
Resistivity ρ=4.3×10−7Ω⋅m
Resistance R=0.05Ω
Step 2: Use the resistance formula R=ρAL to find length L.
Rearranging the formula for L:
L=ρR⋅A
Substitute the values:
L=4.3×10−7Ω⋅m(0.05Ω)×(4.0×10−7m2)
L=4.3×10−7Ω⋅m0.2×10−7Ω⋅m2
L=4.30.2 m
L≈0.04651 m
Rounding to two significant figures:
LengthL=0.047m