We read your photo as:

A piece of floater has a density of 0.30 x 103 kgm⁻³. It floats in a liquid of density 1.30 x 105 kgm⁻³. What fraction of the volume of the floater is immersed?

Physics

ScanSolve AI Answer

Answer

c

313 or approximately 0.2308\frac{3}{13} \text{ or approximately } 0.2308

Step-by-step solution

5 steps

Here are the solutions to the questions from the image:

Part c· 5 steps

Buoyancy Problem

To find the fraction of the volume of the floater immersed, we use the principle of flotation, which states that the weight of the floating object is equal to the weight of the fluid it displaces.

  1. State the principle of flotation.

    Weight of floater = Buoyant force

    ρfVtotalg=ρlVimmersedg\rho_f V_{total} g = \rho_l V_{immersed} g

    where ρf\rho_f is the density of the floater, VtotalV_{total} is the total volume of the floater, ρl\rho_l is the density of the liquid, and VimmersedV_{immersed} is the volume of the floater immersed in the liquid. gg is the acceleration due to gravity.

  2. Simplify the equation by canceling gg from both sides.

    ρfVtotal=ρlVimmersed\rho_f V_{total} = \rho_l V_{immersed}
  3. Rearrange the equation to find the fraction of the volume immersed, VimmersedVtotal\frac{V_{immersed}}{V_{total}}.

    VimmersedVtotal=ρfρl\frac{V_{immersed}}{V_{total}} = \frac{\rho_f}{\rho_l}
  4. Substitute the given values.

    Density of floater (ρf\rho_f) = 0.30×103 kgm−30.30 \times 10^3 \text{ kgm}^{-3}
    Density of liquid (ρl\rho_l) = 1.30×103 kgm−31.30 \times 10^3 \text{ kgm}^{-3}

    VimmersedVtotal=0.30×103 kgm−31.30×103 kgm−3\frac{V_{immersed}}{V_{total}} = \frac{0.30 \times 10^3 \text{ kgm}^{-3}}{1.30 \times 10^3 \text{ kgm}^{-3}}
  5. Calculate the fraction.

    VimmersedVtotal=0.301.30=313\frac{V_{immersed}}{V_{total}} = \frac{0.30}{1.30} = \frac{3}{13}

    As a decimal, this is approximately:

    VimmersedVtotal≈0.2308\frac{V_{immersed}}{V_{total}} \approx 0.2308

    The fraction of the volume of the floater immersed is 313 or approximately 0.2308\boxed{\frac{3}{13} \text{ or approximately } 0.2308}.

Part d(i)

For an **elastic collision

Conditions for Collisions

  • Kinetic energy is conserved. (Momentum is also conserved).

Part d(ii)

For an **inelastic collision

  • Kinetic energy is not conserved. (Momentum is conserved, but some kinetic energy is converted to other forms like heat, sound, or deformation).

9. (a) Heating Curve of a Solid

To draw a heating curve of a solid, you would plot Temperature on the y-axis and Time (or Heat Added) on the x-axis.

The curve would show the following features:

  • Solid phase: An initial upward sloping line, indicating that as heat is added, the temperature of the solid increases.
  • Melting point: A horizontal segment on the graph, representing the constant temperature at which the solid begins to melt into a liquid.
  • Melting phase: This horizontal segment also represents the melting process, where the added heat (latent heat of fusion) is used to change the state from solid to liquid, without a change in temperature. During this phase, both solid and liquid coexist.
  • Liquid phase: After all the solid has melted, the curve becomes an upward sloping line again, indicating that as more heat is added, the temperature of the liquid increases.

Here's a description of how the graph would look:

  1. Start at a low temperature on the y-axis (solid phase).
  2. Draw a line sloping upwards to the right, showing increasing temperature with time.
  3. At a specific temperature (the melting point), draw a horizontal line segment. This is the melting phase.
  4. After the horizontal segment, draw another line sloping upwards to the right, starting from the melting point temperature and continuing to higher temperatures (liquid phase).
Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp