A piece of metal of mass 50g is cooled from 80°C to 20°C. Calculate the amount of heat lost. (Specific heat capacity of the material of metal = 450 Jkg-1k-1. A. 4.50 x 103J. B. 2.5 x 103J. C. 1.80 x 103J. D. 1.35 x 103J. [2000/23])

To calculate the amount of heat lost, we use the formula Q = mc T. Step 1: Identify the given values and convert units. Mass of metal, m = 50 g = 0.050 kg Initial temperature, T_1 = 80 °C Final temperature, T_2 = 20 °C Specific heat capacity, c = 450 J kg^-1 K^-1 Step 2: Calculate the change in temperature ( T). The change in temperature is the difference between the initial and final temperatures. T = T_1 - T_2 = 80 °C - 20 °C = 60 °C Since a change of 1 °C is equal to a change of 1 K, T = 60 K. Step 3: Substitute the values into the heat transfer formula. Q = mc T Q = (0.050 kg) × (450 J kg^-1 K^-1) × (60 K) Step 4: Calculate the amount of heat lost. Q = 0.050 × 450 × 60 J Q = 22.5 × 60 J Q = 1350 J Step 5: Express the answer in scientific notation and compare with the options. Q = 1.35 × 10^3 J This matches option D. The final answer is D. 1.35 × 10^3 J. Send me the next one 📸