A radar signal is beamed toward a planet from earth and is echo is received seven minutes later.The distance between the planet and the earth is 0.00000000063m find the velocity of the signal

Physics

ScanSolve AI Answer

Answer

3.0×10−12 ms3.0 \times 10^{-12}\ \frac{\text{m}}{\text{s}}

Step-by-step solution

3 steps
  1. Convert the time from minutes to seconds.

    The echo is received seven minutes later, so the total time taken for the signal to travel to the planet and back is t=7 minutest = 7\text{ minutes}.

    t=7 minutes×60 sminute=420 st = 7\text{ minutes} \times 60\ \frac{\text{s}}{\text{minute}} = 420\text{ s}
  2. Determine the total distance traveled by the signal.

    The distance between the Earth and the planet is given as d=0.00000000063 md = 0.00000000063\text{ m}.
    The radar signal travels from Earth to the planet and then the echo travels back from the planet to Earth. Therefore, the total distance covered by the signal is twice the distance between the Earth and the planet.

    Total distance=2×d\text{Total distance} = 2 \times d Total distance=2×0.00000000063 m=0.00000000126 m\text{Total distance} = 2 \times 0.00000000063\text{ m} = 0.00000000126\text{ m}
  3. Calculate the velocity of the signal.

    Velocity is calculated as total distance divided by total time.

    Velocity=Total distanceTotal time\text{Velocity} = \frac{\text{Total distance}}{\text{Total time}} v=0.00000000126 m420 sv = \frac{0.00000000126\text{ m}}{420\text{ s}} v=3.0×10−12 msv = 3.0 \times 10^{-12}\ \frac{\text{m}}{\text{s}}

    The velocity of the signal is:

    3.0×10−12 ms3.0 \times 10^{-12}\ \frac{\text{m}}{\text{s}}
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