This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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8. a) The first sound travels directly from the Boy to the Girl. The second sound is an echo, meaning it reflects off the high wall. Sketch: Draw a straight line from "Boy" to "Girl" (this is the path of the first sound). Draw a line from "Boy" to a point on the "High wall", then another line from that point on the "High wall" to "Girl". This represents the path of the second sound (echo). 8. b) Step 1: Calculate the speed of sound (v). The first sound travels directly from the Boy to the Girl, a distance of 200 \, m, in 0.6 \, s. v = DistanceTime v = 200 \, m0.6 \, s v = (1000)/(3) \, m/s ≈ 333.33 \, m/s Step 2: Calculate the total time for the second sound (t_2). The second sound is heard 0.25 \, s after the first sound. t_2 = t_1 + 0.25 \, s t_2 = 0.6 \, s + 0.25 \, s = 0.85 \, s Step 3: Determine the length of the path followed by the second sound (L_2). L_2 = v × t_2 L_2 = (1000)/(3) \, m/s × 0.85 \, s L_2 = (850)/(3) \, m L_2 ≈ 283.33 \, m The length of the path followed by the second sound is 283.33 m. 9. A person standing in an illuminated garden at night having two shadows of different sharpness indicates the presence of multiple light sources. Each light source casts its own shadow. If these light sources are of different sizes, intensities, or are positioned at different distances or angles from the person, they will produce shadows with varying degrees of umbra (darkest part) and penumbra (lighter, fuzzy part), leading to different sharpness. 10. When a positively charged metal sphere is brought near an uncharged metallic object, electrostatic induction occurs. The positive charge on the sphere attracts the free electrons in the uncharged metallic object towards the side closest to it. Therefore, point X will have an induced negative* charge. This movement of electrons leaves a net positive charge on the side furthest from the sphere. Therefore, point Y will have an induced positive* charge. 3 done, 2 left today. You're making progress.