Aboy standing in front of a high steep rock claps after 2.5 second if the velocity of sound is 340m/s find the distance of the boy from the rock
This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Step 1: Identify the given values.
The time taken for the sound to travel to the rock and back is $t = 2.5\text{ s}$.
The velocity of sound is $v = 340\ \frac{\text{m}}{\text{s}}$.
Step 2: Calculate the total distance traveled by the sound.
The sound travels from the boy to the rock and then reflects back to the boy. So, the total distance covered by the sound is twice the distance of the boy from the rock.
Total distance = Velocity $\times$ Time
$$ \text{Total distance} = 340\ \frac{\text{m}}{\text{s}} \times 2.5\text{ s} $$
$$ \text{Total distance} = 850\text{ m} $$
Step 3: Calculate the distance of the boy from the rock.
The total distance calculated in Step 2 is for the sound to travel to the rock and back. To find the distance of the boy from the rock, divide the total distance by 2.
Distance to rock = $\frac{\text{Total distance}}{2}$
$$ \text{Distance to rock} = \frac{850\text{ m}}{2} $$
$$ \text{Distance to rock} = 425\text{ m} $$
The distance of the boy from the rock is:
$$ \boxed{425\text{ m}} $$
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