This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Hey, good to see you again. a) Step 1: Determine the time interval between claps. The girl makes 60 claps in 1 minute (60 seconds). Since each clap coincides with the echo of the one before, the time interval between successive claps is the time it takes for the sound to travel to the wall and back. t = Total timeNumber of claps = 60 s60 = 1 s Step 2: Calculate the speed of sound. The distance to the wall is D = 170 m. The sound travels 2D for an echo. The speed of sound v is given by the formula: v = (2D)/(t) Substitute the values: v = 2 × 170 m1 s v = 340 m/s The speed of sound in air is 340 m/s. b) Step 1: Determine the new time interval between claps. The girl now makes 45 claps in 1 minute (60 seconds). t' = Total timeNumber of claps = 60 s45 = (4)/(3) s Step 2: Calculate the new distance from the wall. Using the speed of sound calculated in part (a), v = 340 m/s, and the new time interval t', the new distance D' is: D' = (v × t')/(2) Substitute the values: D' = 340 m/s × (4)/(3) s2 D' = (340 × 4)/(3 × 2) m D' = (1360)/(6) m D' = (680)/(3) m D' ≈ 226.67 m Her new distance from the wall is 226.67 m. Send me the next one 📸