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A rocket is propelled by a force of 106 N and has a speed of 3000 m/s. What is the power expended?

Physics

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Answer

D. 3×109 watts\text{D. } 3 \times 10^9 \text{ watts}

Step-by-step solution

4 steps

To determine the power expended, we use the formula that relates power, force, and velocity.

  1. Identify the given values.

    The force propelling the rocket is F=106 NF = 10^6 \, \text{N}.
    The speed acquired by the rocket is v=3000 m/sv = 3000 \, \text{m/s}.
    The mass of the rocket is m=40,000 kgm = 40,000 \, \text{kg} (this information is not needed for calculating power directly from force and velocity).

  2. Recall the formula for power.

    Power (PP) is defined as the rate at which work is done, or the product of force and velocity when the force is applied in the direction of motion:

    P=F⋅vP = F \cdot v
  3. Substitute the given values into the formula and calculate the power.

    P=(106 N)×(3000 m/s)P = (10^6 \, \text{N}) \times (3000 \, \text{m/s}) P=3000×106 WP = 3000 \times 10^6 \, \text{W}

    To express this in scientific notation:

    P=3×103×106 WP = 3 \times 10^3 \times 10^6 \, \text{W} P=3×10(3+6) WP = 3 \times 10^{(3+6)} \, \text{W} P=3×109 WP = 3 \times 10^9 \, \text{W}
  4. Compare the result with the given options.

    The calculated power is 3×109 watts3 \times 10^9 \, \text{watts}. This matches option D.

    The final answer is D. 3×109 watts\text{D. } 3 \times 10^9 \text{ watts}.

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