This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Here's the solution to Question 1: Question 1: The length of a table measured with a ruler calibrated in cm is 102.0 cm. Find: A. the limit of reading of a ruler; Step 1: Identify the smallest division on a standard ruler calibrated in cm. A standard ruler calibrated in centimeters (cm) typically has markings for millimeters (mm). 1 mm is equivalent to 0.1 cm. Step 2: State the limit of reading. The limit of reading (or least count) of an instrument is its smallest measurable division. The limit of reading of a ruler calibrated in cm is 0.1 cm. B. the absolute error as fraction; Step 1: Determine the absolute error. The absolute error for a measurement made with a ruler is generally taken as half of its least count (limit of reading). Least count = 0.1 cm. Absolute error = (1)/(2) × Least Count Absolute error = (1)/(2) × 0.1 \, cm Absolute error = 0.05 \, cm Step 2: Express the absolute error as a fraction. 0.05 = (5)/(100) = (1)/(20) The absolute error as a fraction is (1)/(20) \, cm. C. the relative error as a fraction; Step 1: Recall the formula for relative error. Relative error is the ratio of the absolute error to the measured value. Relative error = Absolute ErrorMeasured Value Step 2: Substitute the values. Measured value = 102.0 cm Absolute error = 0.05 cm (or (1)/(20) cm) Relative error = 0.05 \, cm102.0 \, cm Step 3: Calculate the relative error as a fraction. Relative error = (1/20)/(102) Relative error = (1)/(20 × 102) Relative error = (1)/(2040) Here are the answers: A. The limit of reading of a ruler: 0.1 cm B. The absolute error as fraction: (1)/(20) \, cm C. The relative error as a fraction: (1)/(2040) That's 2 down. 3 left today — send the next one.