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A spring requires 12 J of work to compress it by 4 cm. How much work is required to stretch it by 3 cm from its unstretched length?

Physics

ScanSolve AI Answer

Answer

B

6.75 J

Step-by-step solution

4 steps
  1. State the formula for the work done on a spring.

    The work WW done to compress or stretch a spring by a displacement xx from its unstretched length is given by:

    W=12kx2W = \frac{1}{2}kx^2

    where kk is the spring constant.

  2. Convert the given displacements to meters.

    Initial compression x1=4 cm=0.04 mx_1 = 4 \text{ cm} = 0.04 \text{ m}.
    New stretch x2=3 cm=0.03 mx_2 = 3 \text{ cm} = 0.03 \text{ m}.

  3. Use the first set of data to calculate the spring constant kk.

    Given W1=12 JW_1 = 12 \text{ J} for x1=0.04 mx_1 = 0.04 \text{ m}.

    12 J=12k(0.04 m)212 \text{ J} = \frac{1}{2}k(0.04 \text{ m})^2 12=12k(0.0016)12 = \frac{1}{2}k(0.0016) 24=k(0.0016)24 = k(0.0016) k=240.0016k = \frac{24}{0.0016} k=15000 N/mk = 15000 \text{ N/m}
  4. Calculate the work done to stretch the spring by 3 cm3 \text{ cm} using the calculated spring constant.

    We need to find W2W_2 for x2=0.03 mx_2 = 0.03 \text{ m}.

    W2=12kx22W_2 = \frac{1}{2}kx_2^2 W2=12(15000 N/m)(0.03 m)2W_2 = \frac{1}{2}(15000 \text{ N/m})(0.03 \text{ m})^2 W2=12(15000)(0.0009)W_2 = \frac{1}{2}(15000)(0.0009) W2=7500×0.0009W_2 = 7500 \times 0.0009 W2=6.75 JW_2 = 6.75 \text{ J}

    The correct option is B) 6.75 J.

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