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A stone is placed in a beaker of water. The initial volume of water is 30 cm3. After the stone is added, the volume increases to 60 cm3. What is the volume of the stone?

Physics

ScanSolve AI Answer

Step-by-step solution

3 steps
  1. Identify the initial volume (V1).

    From the first beaker in the diagram, the initial volume of water is 30 cm330 \text{ cm}^3.

    V1=30 cm3V1 = 30 \text{ cm}^3
  2. Identify the final volume (V2).

    From the second beaker in the diagram, after the stone is added, the final volume of water is 60 cm360 \text{ cm}^3.

    V2=60 cm3V2 = 60 \text{ cm}^3
  3. Calculate the volume of the stone.

    The volume of the stone is the difference between the final volume and the initial volume.

    Volume of the stone=V2−V1\text{Volume of the stone} = V2 - V1 Volume of the stone=60 cm3−30 cm3\text{Volume of the stone} = 60 \text{ cm}^3 - 30 \text{ cm}^3 Volume of the stone=30 cm3\text{Volume of the stone} = 30 \text{ cm}^3

    Initial volume - V1 = 30 cm3\boxed{\text{30 cm}^3}
    Final volume - V2 = 60 cm3\boxed{\text{60 cm}^3}
    Volume of the stone = 30 cm3\boxed{\text{30 cm}^3}

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