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A student investigates the stretching of a spring. Calculate the extension e of the spring using the equation e = (l − l0) when L = 5.00 N. Plot a graph of L (N) against e (cm).

Physics

ScanSolve AI Answer

Answer

11

21.6 cm21.6 \text{ cm}

Step-by-step solution

3 steps

Here are the solutions to the questions:

Part 11· 3 steps

A student investigates the stretching of a spring.

Calculate the extension e of the spring using the equation e = (l - l0) when L = 5.00 N. Record this value of e in Table 1.

  1. Identify the unstretched length (l0l_0) from Table 1.

    From Table 1, when L = 0.00 N, the length l=2.1 cml = 2.1 \text{ cm}.
    So, l0=2.1 cml_0 = 2.1 \text{ cm}.

  2. Identify the stretched length (ll) for L = 5.00 N from Table 1.

    From Table 1, when L = 5.00 N, the length l=23.7 cml = 23.7 \text{ cm}.

  3. Calculate the extension (ee).

    e=l−l0e = l - l_0 e=23.7 cm−2.1 cme = 23.7 \text{ cm} - 2.1 \text{ cm} e=21.6 cme = 21.6 \text{ cm}

    The value to be recorded in Table 1 for L = 5.00 N is 21.6 cm\boxed{21.6 \text{ cm}}.

    The completed Table 1 is:

    L/Nl/cme/cm
    0.002.10.0
    1.006.03.9
    2.0010.68.5
    3.0014.912.8
    4.0019.317.2
    5.0023.721.6

Part c

Plot a graph of L (N) (y-axis) against e (cm) (x-axis). Start both axes at the origin (0, 0). Draw the best-fit line.

To plot the graph:

  1. Draw Axes: Draw two perpendicular axes. Label the vertical axis "Load L (N)" and the horizontal axis "Extension e (cm)".
  2. Choose Scale: Select appropriate scales for both axes.
    • For the x-axis (Extension e): The values range from 0.0 cm to 21.6 cm. A suitable scale would be 1 cm representing 1 cm of extension (or 2 cm representing 1 cm of extension for a larger graph).
    • For the y-axis (Load L): The values range from 0.00 N to 5.00 N. A suitable scale would be 2 cm representing 1 N of load.
  3. Origin: Ensure both axes start at the origin (0,0).
  4. Plot Points: Plot the following data points (e, L) from the completed Table 1:
    • (0.
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