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A student is asked to calculate hydrostatic pressure, determine factors affecting manhole size, identify the standard waste pipe diameter for a wash hand basin, and to describe how to test the straigh

Physics

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Answer

A

14.7 kN/m214.7 \text{ kN/m}^2

Step-by-step solution

5 steps

Here are the solutions to the questions:

Part 6· 2 steps

To find the intensity pressure (hydrostatic pressure), we use the formula:

P=ρghP = \rho g h

where:
ρ\rho (density of water) =1000 kg/m3= 1000 \text{ kg/m}^3
gg (acceleration due to gravity) =9.81 m/s2= 9.81 \text{ m/s}^2
hh (depth of water) =1.5 m= 1.5 \text{ m}

  1. Substitute the values into the formula.

    P=1000 kg/m3×9.81 m/s2×1.5 mP = 1000 \text{ kg/m}^3 \times 9.81 \text{ m/s}^2 \times 1.5 \text{ m}
  2. Calculate the pressure.

    P=14715 N/m2P = 14715 \text{ N/m}^2

    To convert to kN/m2\text{kN/m}^2, divide by 1000:

    P=14.715 kN/m2P = 14.715 \text{ kN/m}^2

    This is approximately 14.7 kN/m214.7 \text{ kN/m}^2.

    The correct option is A. 14.7 kN/m214.7 \text{ kN/m}^2.

Part 7

When determining the size of a manhole, factors like the number of incoming drain pipes, the depth of the manhole, and the size of the drain pipes are all applicable as they directly influence the required dimensions and structural design. The type of discharge (e.g., foul water, surface water) primarily influences the materials used and specific internal features (like benching profile) rather than the overall physical size of the manhole itself.

The correct option is D. Type of discharge to the man hole.

Part 8

For a wash hand basin, the standard size/diameter of the waste drain pipe is typically 32mm.

The correct option is B. 32mm.

Part 9

To test for the straightness of a drain line, a light test is commonly used. A light is shone from one end of the pipe, and if the line is straight and clear, a full circle of light will be visible from the other end.

The correct option is C. Light test.

Part 10· 3 steps

To convert temperature from Celsius (∘C^\circ\text{C}) to Fahrenheit (∘F^\circ\text{F}), use the formula:

F=C×95+32F = C \times \frac{9}{5} + 32

Given C=65∘CC = 65^\circ\text{C}.

  1. Substitute the Celsius temperature into the formula.

    F=65×95+32F = 65 \times \frac{9}{5} + 32
  2. Perform the multiplication.

    F=13×9+32F = 13 \times 9 + 32 F=117+32F = 117 + 32
  3. Perform the addition.

    F=149∘FF = 149^\circ\text{F}

    The correct option is C. 149∘F149^\circ\text{F}.

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