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A student is performing an experiment with a helical spring and collecting data for the period T and mass m. They need to plot a graph of T2 vs m, determine the slope and intercept, and calculate the

Physics

ScanSolve AI Answer

Answer

M\textbf{M}

Step-by-step solution

5 steps

Okay, Pretty~Nelly, let's break down this experiment on the helical spring.

  1. Address Question 8 (Plotting the graph)

    I cannot plot a graph directly. However, if you were to plot the graph, you would use the experimental data with T2T^2 values on the y-axis and corresponding mm values on the x-axis. The resulting graph should be a straight line.

  2. Determine the slope, SS, and the value of KK (Question 9)

    The given equation for the period of a mass-spring system is:

    T2=4π2Km+4π2KMT^2 = \frac{4\pi^2}{K}m + \frac{4\pi^2}{K}M

    This equation is in the form of a straight line y=Sgraphx+Cy = S_{graph}x + C, where y=T2y = T^2, x=mx = m.
    The slope of the graph, SgraphS_{graph}, would be determined from your plotted graph using two points (m1,T12)(m_1, T_1^2) and (m2,T22)(m_2, T_2^2):

    Sgraph=ΔT2Δm=T22−T12m2−m1S_{graph} = \frac{\Delta T^2}{\Delta m} = \frac{T_2^2 - T_1^2}{m_2 - m_1}

    Once you have the numerical value for SgraphS_{graph} from your graph, you can find the spring constant KK:

    Sgraph=4π2KS_{graph} = \frac{4\pi^2}{K} K=4π2SgraphK = \frac{4\pi^2}{S_{graph}}

    The physical significance of KK is the spring constant (or force constant) of the helical spring. It measures the stiffness of the spring, indicating the force required to extend or compress the spring by a unit length. Its unit is Newtons per meter (N/m\text{N/m}).

  3. Determine the intercept, CC, and calculate μ\mu (Question 10)

    The intercept CC is the value of T2T^2 when m=0m=0. This can be read directly from your plotted graph where the line crosses the T2T^2 (y-axis).
    From the equation, the intercept is C=4π2KMC = \frac{4\pi^2}{K}M.
    Once you have the numerical values for CC and SgraphS_{graph} from your graph, you can calculate μ\mu:

    μ=CSgraph\mu = \frac{C}{S_{graph}}

    Substituting the expressions for CC and SgraphS_{graph}:

    μ=4π2KM4π2K\mu = \frac{\frac{4\pi^2}{K}M}{\frac{4\pi^2}{K}} μ=M\mu = \boxed{\textbf{M}}
  4. Physical significance of μ\mu (Question 11)

    As derived in Step 3, μ=M\mu = M.
    The physical significance of μ\mu (or MM) is the effective mass of the spring. In an oscillating mass-spring system, the spring itself has mass, and a portion of this mass contributes to the total oscillating mass. This effective mass is typically one-third of the actual mass of the spring.

  5. State any precautions taken (Question 12)

    • Ensure the oscillations are purely vertical and not swinging sideways.
    • Avoid parallax error when reading the stopwatch and the mass values.
    • Ensure the spring is not stretched beyond its elastic limit to maintain Hooke's Law.
    • Take multiple readings for the time of a large number of oscillations (e.g., 10 or 20) to minimize the human reaction time error in starting and stopping the stopwatch.
    • Start and stop the stopwatch when the mass is at the same point in its oscillation (e.g., highest point, lowest point, or passing through the equilibrium position in the same direction).
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