A wave has a frequency of 50HZ and a wave length of 40cm Calculate The distance btw successive Crest The Wave speed The period of time

Physics

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Answer

40 cm\text{40 cm}

v=20 m/sv = \text{20 m/s}

T=0.02 sT = \text{0.02 s}

Step-by-step solution

3 steps
  1. Calculate the distance between successive crests.

    The distance between successive crests is defined as the wavelength (λ\lambda).
    The wavelength is given as 40 cm40 \text{ cm}.

    Distance between successive crests=λ=40 cm\text{Distance between successive crests} = \lambda = \boxed{\text{40 cm}}
  2. Calculate the wave speed.

    The wave speed (vv) is calculated using the formula v=fλv = f \lambda, where ff is the frequency and λ\lambda is the wavelength.
    Given:
    Frequency (ff) = 50 Hz50 \text{ Hz}
    Wavelength (λ\lambda) = 40 cm=0.40 m40 \text{ cm} = 0.40 \text{ m}

    Substitute the values into the formula:

    v=fλv = f \lambda v=(50 Hz)×(0.40 m)v = (50 \text{ Hz}) \times (0.40 \text{ m}) v=20 m/sv = \boxed{\text{20 m/s}}
  3. Calculate the period of time.

    The period (TT) is the reciprocal of the frequency (ff).
    The formula is T=1fT = \frac{1}{f}.
    Given:
    Frequency (ff) = 50 Hz50 \text{ Hz}

    Substitute the value into the formula:

    T=1fT = \frac{1}{f} T=150 HzT = \frac{1}{50 \text{ Hz}} T=0.02 sT = \boxed{\text{0.02 s}}
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