A) What is the density of the alloy? b) What is the mass of tin in 0.02 m3 of the alloy?

• Mass percentage of aluminum ($w_{Al}$) = 60% = 0.60
• Mass percentage of tin ($w_{Sn}$) = 40% = 0.40
• Density of aluminum ($\rho_{Al}$) = $2700 \text{ kg/m}^3$
• Density of tin ($\rho_{Sn}$) = $7300 \text{ kg/m}^3$

The density of an alloy ($\rho_{alloy}$) when given mass fractions ($w_i$) and individual densities ($\rho_i$) is:

Calculate the terms in the denominator:

Sum the terms:

Now, take the reciprocal:

Rounding to three significant figures:
The density of the alloy is $\boxed{\text{3610 kg/m}^3}$.

Use the density calculated in part (a):

The alloy consists of 40% tin by weight (mass).

Rounding to three significant figures:
The mass of tin is $\boxed{\text{28.9 kg}}$.