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An aircraft with an initial mass of 1950 kg has cargo of 450 kg added at a distance of 1.75 m from its original center of gravity. Calculate the shift in the center of gravity in cm.

Physics

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Step-by-step solution

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To calculate the shift in the center of gravity (CG) when mass is added, we use the formula:

ΔCG=Madded×dMinitial+Madded\Delta CG = \frac{M_{added} \times d}{M_{initial} + M_{added}}

where:
MaddedM_{added} is the mass added.
dd is the distance of the added mass from the original CG.
MinitialM_{initial} is the initial mass of the aircraft.

  1. Identify the given values.

    Initial mass of aircraft (MinitialM_{initial}) = 1950 kg
    Mass added (MaddedM_{added}) = 450 kg
    Distance of added mass from the original CG (dd) = 1.75 m

  2. Calculate the total mass after adding the cargo.

    Mtotal=Minitial+MaddedM_{total} = M_{initial} + M_{added} Mtotal=1950 kg+450 kg=2400 kgM_{total} = 1950 \text{ kg} + 450 \text{ kg} = 2400 \text{ kg}
  3. Calculate the shift in the center of gravity.

    ΔCG=Madded×dMtotal\Delta CG = \frac{M_{added} \times d}{M_{total}} ΔCG=450 kg×1.75 m2400 kg\Delta CG = \frac{450 \text{ kg} \times 1.75 \text{ m}}{2400 \text{ kg}} ΔCG=787.52400 m\Delta CG = \frac{787.5}{2400} \text{ m} ΔCG=0.328125 m\Delta CG = 0.328125 \text{ m}
  4. Convert the shift in CG from meters to centimeters.

    ΔCG=0.328125 m×100cmm\Delta CG = 0.328125 \text{ m} \times 100 \frac{\text{cm}}{\text{m}} ΔCG=32.8125 cm\Delta CG = 32.8125 \text{ cm}
  5. Round the result to the nearest whole number and select the closest option.

    The calculated shift is approximately 33 cm.

    Comparing this to the given options:
    A) 34 cm
    B) 30 cm
    C) 33 cm
    D) 40 cm

    The closest option is C.

    The loaded CG will move by:

    C) 33 cm\boxed{\text{C) 33 cm}}
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