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An airplane is flying south at 100 km/hr. A wind is blowing west at 25 km/hr. What is the resultant velocity of the airplane?

Physics

ScanSolve AI Answer

Answer

A

Step-by-step solution

3 steps
  1. Identify the given velocities as vectors.

    The airplane's velocity is 100 km/hr South100 \text{ km/hr South}. We can represent this as a vector pointing downwards.
    The wind's velocity is 25 km/hr West25 \text{ km/hr West}. We can represent this as a vector pointing to the left.
    Since these velocities are perpendicular, we can use the Pythagorean theorem to find the magnitude of the net velocity.

  2. Calculate the magnitude of the net velocity.

    Let VpV_p be the airplane's speed and VwV_w be the wind's speed.
    The net velocity VnetV_{net} is the hypotenuse of a right-angled triangle formed by VpV_p and VwV_w.

    Vnet=Vp2+Vw2V_{net} = \sqrt{V_p^2 + V_w^2}

    Substitute the given values:

    Vnet=(100 km/hr)2+(25 km/hr)2V_{net} = \sqrt{(100 \text{ km/hr})^2 + (25 \text{ km/hr})^2} Vnet=10000 km2/hr2+625 km2/hr2V_{net} = \sqrt{10000 \text{ km}^2/\text{hr}^2 + 625 \text{ km}^2/\text{hr}^2} Vnet=10625 km2/hr2V_{net} = \sqrt{10625 \text{ km}^2/\text{hr}^2} Vnet≈103.0776 km/hrV_{net} \approx 103.0776 \text{ km/hr}
  3. Round the result and select the correct option.

    Rounding to one decimal place, the net velocity is approximately 103.1 km/hr103.1 \text{ km/hr}.
    Comparing this with the given options:
    A. 103.1 km/hr103.1 \text{ km/hr}
    B. 75.0 km/hr75.0 \text{ km/hr}
    C. 125 km/hr125 \text{ km/hr}
    D. 26.9 km/hr26.9 \text{ km/hr}

    The correct option is A.

    The final answer is A. 103.1 km/hr\boxed{\text{A. } 103.1 \text{ km/hr}}.

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