This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Haya Jozee, hebu tuendelee na hili. Step 1: Andika formula ya voltage ya papo hapo (instantaneous voltage) wakati inaanza kutoka thamani ya juu zaidi (positive maximum). Kwa sababu muda unapimwa kutoka thamani ya juu zaidi chanya, tunatumia kazi ya kosine: V = V₀ cos(2πft) Ambapo: V = voltage ya papo hapo (instantaneous voltage) V₀ = voltage ya juu zaidi (maximum voltage) f = marudio (frequency) t = muda Step 2: Badilisha thamani zinazojulikana kwenye formula. Tunapewa: V₀ = 282.8 V f = 50 Hz V = 141.4 V 141.4 V = 282.8 V × cos(2π × 50 Hz × t) Step 3: Tengeneza cos(2πft) peke yake. cos(2π × 50t) = 141.4 V / 282.8 V cos(100πt) = 0.5 Step 4: Tafuta thamani ya 100πt kwa kutumia inverse cosine. 100πt = arccos(0.5) Tunajua kuwa arccos(0.5) ni π/3 radians. 100πt = π/3 Step 5: Tatua kwa t. t = (π/3) / (100π) t = 1 / (3 × 100) t = 1 / 300 s Muda uliopimwa kutoka thamani ya juu zaidi chanya ambapo voltage ya papo hapo itakuwa 141.4 V ni 1/300 sekunde au takriban 0.00333 sekunde. That's 2 down. 3 left today — send the next one.