This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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Answer
V₀ / √(2)
Hebu tutatue hili:
Step 1: Tafuta voltage ya kilele (peak voltage), V₀. Voltage ya AC ya 220 V ni RMS voltage (V_rms). Ili kupata voltage ya kilele (V₀), tunatumia formula: V_rms = V₀ / √(2) Hivyo, V₀ = V_rms × √(2)
V₀ = 220 V × √(2) V₀ = 220 V × 1.414 V₀ = 311.08 V
Step 2: Tumia formula ya wastani wa EMF (average EMF) kwa nusu mzunguko chanya. Kwa wimbi la sine, wastani wa EMF (V_avg) wakati wa nusu mzunguko chanya hutolewa na formula: V_avg = (2V₀) / π
Step 3: Badilisha thamani ya V₀ na ukokotoe. V_avg = (2 × 311.08 V) / π V_avg = 622.16 V / 3.14159 V_avg = 198.04 V
Wastani wa EMF wakati wa nusu mzunguko chanya ni 198.04 V.
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Hebu tutatue hili: Step 1: Tafuta voltage ya kilele (peak voltage), V₀. Voltage ya AC ya 220 V ni RMS voltage (V_rms).
This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.