An object of 10 kg is raised through 8m calculate its potential energy. State 4 energy conversion. An electric motor rated at 1.5KW is used to lift 300kg load through 600cm. The motor has an efficiency of 80%. Calculate a) Potention energy gained by the load.

Given:

• Mass, $m = 10 \, \text{kg}$
• Height, $h = 8 \, \text{m}$
• Acceleration due to gravity, $g = 9.81 \, \text{m/s}^2$ The formula for potential energy (PE) is:

$$PE = mgh$$

$$PE = (10 \, \text{kg}) \times (9.81 \, \text{m/s}^2) \times (8 \, \text{m})$$ $$PE = 784.8 \, \text{J}$$

The potential energy of the object is $\boxed{\text{784.8 J}}$.

: Potential Energy Gained by a Load

Given:

• Mass, $m = 300 \, \text{kg}$
• Height, $h = 600 \, \text{cm}$
• Acceleration due to gravity, $g = 9.81 \, \text{m/s}^2$ Convert height from centimeters to meters:

$$h = 600 \, \text{cm} \times \frac{1 \, \text{m}}{100 \, \text{cm}} = 6 \, \text{m}$$

The formula for potential energy (PE) is:

$$PE = mgh$$

$$PE = (300 \, \text{kg}) \times (9.81 \, \text{m/s}^2) \times (6 \, \text{m})$$ $$PE = 17658 \, \text{J}$$

The potential energy gained by the load is $\boxed{\text{17658 J}}$.