This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Alright Rose — let's do this. Here's how to solve question 15 (b): b) A bullet was released from a hunter's gun with an initial velocity of 8 m/s. It then accelerates at 3.5 m/s^2 for 15 seconds. Step 1: Calculate the final velocity of the bullet. We use the equation of motion v = u + at, where u is initial velocity, a is acceleration, and t is time. v = 8 m/s + (3.5 m/s^2)(15 s) v = 8 m/s + 52.5 m/s v = 60.5 m/s The final velocity of the bullet is 60.5 m/s. Step 2: Calculate the distance traveled by the bullet. We use the equation of motion s = ut + (1)/(2)at^2, where s is distance, u is initial velocity, a is acceleration, and t is time. s = (8 m/s)(15 s) + (1)/(2)(3.5 m/s^2)(15 s)^2 s = 120 m + (1)/(2)(3.5 m/s^2)(225 s^2) s = 120 m + (1.75 m/s^2)(225 s^2) s = 120 m + 393.75 m s = 513.75 m The distance traveled by the bullet is 513.75 m. Send me the next one 📸