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Describe the behavior of parallel conductors with currents in opposite directions and waves moving from deep to shallow medium.

Physics

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9)

i) When currents flow in opposite directions in parallel conductors, the conductors repel each other.

  • For conductor A, the force F\text{F} will be directed to the left (away from B).
  • For conductor B, the force F\text{F} will be directed to the right (away from A).
\begin{tikzpicture}[scale=0.8] % Conductor A \draw (0,0) circle (0.5); \node at (0,0) {$\odot$}; % Current out of page \node at (0,1) {A}; % Conductor B \draw (4,0) circle (0.5); \node at (4,0) {$\otimes$}; % Current into page \node at (4,1) {B}; % Magnetic field lines (simplified representation for repulsion) \draw[->] (2, -2) arc (-90:90:2 and 2); \draw[->] (2, 2) arc (90:270:2 and 2); % Forces \draw[->, thick, red] (0,0) -- (-1,0); \node[red] at (-1.3,0) {F}; \draw[->, thick, red] (4,0) -- (5,0); \node[red] at (5.3,0) {F}; \end{tikzpicture}

10)
When waves travel from a deep to a shallow medium, their speed decreases, and their wavelength decreases. If they approach the boundary at an angle, they also refract (bend) towards the normal. The wave crests in the shallow medium will be closer together and bent.

\begin{tikzpicture}[scale=0.8] % Deep medium waves \foreach \x in {-2,-1,0,1,2} { \draw (\x, -2) -- (\x, 2); } \draw[->] (0.5, 0) -- (1.5, 0); % Direction of propagation \node at (0, -2.5) {Deep}; % Boundary \draw[thick] (2,-2) -- (4,2); \node at (4.5, 2.5) {Shallow}; % Shallow medium waves (refracted and shorter wavelength) \draw (2.2, -1.8) -- (3.2, 0.2); \draw (2.4, -1.4) -- (3.4, 0.6); \draw (2.6, -1.0) -- (3.6, 1.0); \draw (2.8, -0.6) -- (3.8, 1.4); \draw (3.0, -0.2) -- (4.0, 1.8); \end{tikzpicture}

Radioactive decay question (unnumbered):

  1. Convert the total time to minutes.

    Total time=1 hour=60 minutes\text{Total time} = 1 \text{ hour} = 60 \text{ minutes}
  2. Calculate the number of half-lives (nn).

    n=Total timeHalf-life=60 minutes20 minutes=3n = \frac{\text{Total time}}{\text{Half-life}} = \frac{60 \text{ minutes}}{20 \text{ minutes}} = 3
  3. Calculate the mass remaining after 3 half-lives.

    Mass remaining=Initial mass×(12)n\text{Mass remaining} = \text{Initial mass} \times \left(\frac{1}{2}\right)^n Mass remaining=20 g×(12)3\text{Mass remaining} = 20 \text{ g} \times \left(\frac{1}{2}\right)^3 Mass remaining=20 g×18\text{Mass remaining} = 20 \text{ g} \times \frac{1}{8} Mass remaining=2.5 g\text{Mass remaining} = 2.5 \text{ g}
  4. Calculate the mass decayed.

    Mass decayed=Initial mass−Mass remaining\text{Mass decayed} = \text{Initial mass} - \text{Mass remaining} Mass decayed=20 g−2.5 g\text{Mass decayed} = 20 \text{ g} - 2.5 \text{ g} Mass decayed=17.5 g\text{Mass decayed} = \boxed{\text{17.5 g}}

    11)
    Two dangers of X-rays are:

    • They are ionizing radiation and can cause cell damage or mutations in DNA, leading to cancer.
    • Excessive exposure can cause radiation sickness, leading to symptoms like nausea, vomiting, hair loss, and fatigue.
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