This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

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Answer
the center of gravity of the 100 cm uniform wooden bar is at
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Here's how to determine the center of gravity of the uniform wooden bar:
Diagram (2 marks)
\begin{tikzpicture % Bar \draw[thick, fill=brown!30] (0,0) rectangle (10,0.5); \node at (5, 0.75) {Wooden Bar (100 cm)}; \node at (0, -0.2) {0 cm}; \node at (10, -0.2) {100 cm}; % Prism (fulcrum) \draw[thick, fill=gray!30] (4.5,-0.5) -- (5.5,-0.5) -- (5,0) -- cycle; \node at (5, -0.75) {Triangular Prism}; % Center of Gravity \draw[dashed] (5, 0.5) -- (5, -0.5); \node[below] at (5, -0.5) {Pivot Point}; \node[above] at (5, 0.5) {Center of Gravity}; \node at (5, -0.2) {50 cm}; \end{tikzpicture} }Method/Precaution (4 marks)
Observation (2 marks)
The uniform wooden bar balances horizontally when supported at its midpoint. For a 100 cm bar, this balancing point is observed to be at the 50 cm mark from either end.
Inference/Conclusion (2 marks)
The point at which a uniform object balances freely is its center of gravity. For a uniform wooden bar, the center of gravity is located at its geometrical center. Therefore, the center of gravity of the 100 cm uniform wooden bar is at 50 cm from either end.
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Welcome back Pretty~Nelly — missed you this week.
This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.