Complete the table with experimental results for time taken for a cross to become invisible.

The table in your image is incomplete because the "Time taken for the cross to become invisible [in seconds]" values are experimental results. These values cannot be calculated from the provided text; they must be obtained by performing the experiment.

To demonstrate how to complete the table, I will use hypothetical time values. In a real experiment, you would record these times yourself.

Hypothetical Time Values (for demonstration purposes only):

• Expt 1: $30 \text{ s}$
• Expt 2: $45 \text{ s}$
• Expt 3: $60 \text{ s}$
• Expt 4: $90 \text{ s}$
• Expt 5: $120 \text{ s}$

Step 1: Calculate the reciprocal of the hypothetical time ($\frac{1}{t}$) for each experiment.

For Experiment 1:

$$\frac{1}{t_1} = \frac{1}{30 \text{ s}} = \boxed{\text{0.0333 s}^{-1}}$$

For Experiment 2:

$$\frac{1}{t_2} = \frac{1}{45 \text{ s}} = \boxed{\text{0.0222 s}^{-1}}$$

For Experiment 3:

$$\frac{1}{t_3} = \frac{1}{60 \text{ s}} = \boxed{\text{0.0167 s}^{-1}}$$

For Experiment 4:

$$\frac{1}{t_4} = \frac{1}{90 \text{ s}} = \boxed{\text{0.0111 s}^{-1}}$$

For Experiment 5:

$$\frac{1}{t_5} = \frac{1}{120 \text{ s}} = \boxed{\text{0.0083 s}^{-1}}$$

Here is the completed table with the hypothetical time values and calculated $\frac{1}{t}$ values:

Expt	1	2	3	4	5
Volume of solution P ($\text{cm}^3$)	25	20	15	10	5
Volume of water added to solution P ($\text{cm}^3$)	0	5	10	15	20
Volume of solution N ($\text{cm}^3$)	10	10	10	10	10
Time taken for the cross to become invisible [in seconds]	*30