From Table 1.1, identify the anomalous result and use it to calculate the average time taken for 8 oscillations. Determine the time T taken for one complete oscillation.

Here are the solutions to the questions:

Question 1 (c):

• i) From Table 1.1, identify the anomalous result. The times recorded are 11.0 s, 11.9 s, 10.8 s, 11.1 s, and 11.2 s. Most values are clustered around 10.8 s to 11.2 s. The value 11.9 s is significantly higher than the others. Anomalous result: $\boxed{\text{11.9 s}}$

• ii) Use Table 1.1 to calculate the average time taken for 8 oscillations.

  • Step 1: Exclude the anomalous result. The anomalous result is 11.9 s. We will use the remaining values: 11.0 s, 10.8 s, 11.1 s, 11.2 s.
  • Step 2: Calculate the sum of the remaining times. $$\text{Sum} = 11.0 + 10.8 + 11.1 + 11.2 = 44.1 \text{ s}$$
  • Step 3: Calculate the average time. Divide the sum by the number of readings used (4). $$\text{Average time} = \frac{44.1 \text{ s}}{4} = 11.025 \text{ s}$$ Rounding to an appropriate number of significant figures (e.g., one decimal place as in the data): Average time taken for 8 oscillations: $\boxed{\text{11.0 s}}$

• iii) Determine the time T taken for one complete oscillation.

  • Step 1: Use the average time for 8 oscillations. From part (ii), the average time for 8 oscillations is 11.025 s (or 11.0 s if rounded).
  • Step 2: Divide by the number of oscillations. The time for one complete oscillation (period T) is the average time for 8 oscillations divided by 8. $$T = \frac{\text{Average time for 8 oscillations}}{8}$$ $$T = \frac{11.025 \text{ s}}{8}$$ $$T = 1.378125 \text{ s}$$ Rounding to an appropriate number of significant figures (e.g., two decimal places): $$T = \boxed{\text{1.38 s}}$$