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Explain the concepts of electrical energy and power, including their commercial units and the principles of power transmission.

Physics

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Here are notes based on the objectives for Electrical Energy and Power:

  • i) Concepts of electrical energy and power & applying expressions to solve problems:

    • Electrical Energy (EE) is the work done by electric current. It is measured in Joules (J). E=VIt=I2Rt=V2RtE = VIt = I^2Rt = \frac{V^2}{R}t
    • Electrical Power (PP) is the rate at which electrical energy is consumed or produced. It is measured in Watts (W). P=VI=I2R=V2RP = VI = I^2R = \frac{V^2}{R}
  • ii) Commercial unit of electric energy and power: The commercial unit of electrical energy is the kilowatt-hour (kWh).

    1 kWh=1000 W×3600 s=3.6×106 J1 \text{ kWh} = 1000 \text{ W} \times 3600 \text{ s} = 3.6 \times 10^6 \text{ J}

    Power is typically measured in Watts (W) or kilowatts (kW) for commercial purposes.

  • iii) Electric power transmission & analyzing how power is transmitted:

    • Electricity is generated at power stations and transmitted over long distances at very high voltages (e.g., hundreds of kilovolts) to minimize power loss.
    • Step-up transformers increase the voltage at the power station.
    • Power loss in transmission cables is given by Ploss=I2RcableP_{loss} = I^2R_{cable}. By increasing voltage (VV), the current (II) for a given power (P=VIP=VI) is reduced, significantly decreasing I2RI^2R losses.
    • Step-down transformers reduce the voltage for distribution to homes and industries for safety and usability.
  • iv) Heating effects of electric current & its uses:

    • The heating effect of electric current (Joule heating) occurs when current flows through a resistor, converting electrical energy into heat energy. The heat produced is H=I2RtH = I^2Rt.
    • Uses: Electric heaters, toasters, kettles, electric irons, incandescent light bulbs, and fuses.
  • v) Electrical wiring of houses & advantages of parallel arrangement over series:

    • Houses are wired in a parallel arrangement.
    • Advantages of parallel wiring:
      • Each appliance receives the full supply voltage.
      • Appliances can be switched on and off independently.
      • If one appliance fails, others continue to operate.
    • Disadvantages of series wiring: Appliances would not receive full voltage, could not be operated independently, and the failure of one would break the entire circuit.
  • vi) Use of fuses & determining the fuse rating:

    • A fuse is a safety device that protects electrical circuits and appliances from overcurrent. It contains a thin wire that melts and breaks the circuit if the current exceeds a safe limit.
    • The fuse rating is the maximum current a fuse can carry continuously without melting.
    • To determine the fuse rating for an appliance, calculate its normal operating current using the formula I=PVI = \frac{P}{V}, where PP is the power of the appliance and VV is the supply voltage. The fuse rating should be slightly higher than this calculated current.
    • For example, a 2400 W appliance on a 240 V supply draws I=2400 W240 V=10 AI = \frac{2400 \text{ W}}{240 \text{ V}} = 10 \text{ A}. A 13 A fuse would be appropriate.
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