This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Here are the conversions for the given physical quantities: 1) Convert 365 cm to m. Step 1: Recall the conversion factor between centimeters and meters. 1 m = 100 cm Step 2: Divide the given value in centimeters by 100. 365 cm × 1 m100 cm = 3.65 m The converted value is 3.65 m. 2) Convert 22400 cm^3 to dm^3 and then to m^3. a) Convert 22400 cm^3 to dm^3. Step 1: Recall the conversion factor between centimeters and decimeters, and then cube it for volume. 1 dm = 10 cm 1 dm^3 = (10 cm)^3 = 1000 cm^3 Step 2: Divide the given value in cubic centimeters by 1000. 22400 cm^3 × 1 dm^31000 cm^3 = 22.4 dm^3 The converted value is 22.4 dm^3. b) Convert 22.4 dm^3 to m^3. Step 1: Recall the conversion factor between decimeters and meters, and then cube it for volume. 1 m = 10 dm 1 m^3 = (10 dm)^3 = 1000 dm^3 Step 2: Divide the value in cubic decimeters by 1000. 22.4 dm^3 × 1 m^31000 dm^3 = 0.0224 m^3 The converted value is 0.0224 m^3. 3) Convert 760 torr to N · m^-2. Step 1: Recall the relationship between torr and standard atmospheric pressure, and its equivalent in Pascals. Note that 1 N · m^-2 = 1 Pa. 760 torr = 1 atm 1 atm = 101325 Pa Step 2: Substitute the value. 760 torr = 101325 Pa 760 torr = 101325 N · m^-2 The converted value is 101325 N · m^-2.