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Convert 365 cm to m and 22400 cm3 to dm3 and then to m3. Also convert 760 torr to N/m2.

Physics

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Answers

2 parts
a

22.4 dm3\text{22.4 dm}^3

b

0.0224 m3\text{0.0224 m}^3

101325 N⋅m−2\text{101325 N} \cdot \text{m}^{-2}

Step-by-step solution

6 steps

Here are the conversions for the given physical quantities:

  1. Convert 365 cm365 \text{ cm} to m\text{m}.

Step 1: Recall the conversion factor between centimeters and meters.

1 m=100 cm1 \text{ m} = 100 \text{ cm}

Step 2: Divide the given value in centimeters by 100.

365 cm×1 m100 cm=3.65 m365 \text{ cm} \times \frac{1 \text{ m}}{100 \text{ cm}} = 3.65 \text{ m}

The converted value is 3.65 m\boxed{\text{3.65 m}}.

  1. Convert 22400 cm322400 \text{ cm}^3 to dm3\text{dm}^3 and then to m3\text{m}^3.

Part a· 2 steps

Convert 22400 cm322400 \text{ cm}^3 to dm3\text{dm}^3.

  1. Recall the conversion factor between centimeters and decimeters, and then cube it for volume.

    1 dm=10 cm1 \text{ dm} = 10 \text{ cm} 1 dm3=(10 cm)3=1000 cm31 \text{ dm}^3 = (10 \text{ cm})^3 = 1000 \text{ cm}^3
  2. Divide the given value in cubic centimeters by 1000.

    22400 cm3×1 dm31000 cm3=22.4 dm322400 \text{ cm}^3 \times \frac{1 \text{ dm}^3}{1000 \text{ cm}^3} = 22.4 \text{ dm}^3

    The converted value is 22.4 dm3\boxed{\text{22.4 dm}^3}.

Part b

0.0224 m3\text{0.0224 m}^3

Convert 22.4 dm322.4 \text{ dm}^3 to m3\text{m}^3.

  1. Recall the conversion factor between decimeters and meters, and then cube it for volume.

    1 m=10 dm1 \text{ m} = 10 \text{ dm} 1 m3=(10 dm)3=1000 dm31 \text{ m}^3 = (10 \text{ dm})^3 = 1000 \text{ dm}^3
  2. Divide the value in cubic decimeters by 1000.

    22.4 dm3×1 m31000 dm3=0.0224 m322.4 \text{ dm}^3 \times \frac{1 \text{ m}^3}{1000 \text{ dm}^3} = 0.0224 \text{ m}^3

    The converted value is 0.0224 m3\boxed{\text{0.0224 m}^3}.

    1. Convert 760 torr760 \text{ torr} to N⋅m−2\text{N} \cdot \text{m}^{-2}.
  3. Recall the relationship between torr and standard atmospheric pressure, and its equivalent in Pascals.

    Note that 1 N⋅m−2=1 Pa1 \text{ N} \cdot \text{m}^{-2} = 1 \text{ Pa}.

    760 torr=1 atm760 \text{ torr} = 1 \text{ atm} 1 atm=101325 Pa1 \text{ atm} = 101325 \text{ Pa}
  4. Substitute the value.

    760 torr=101325 Pa760 \text{ torr} = 101325 \text{ Pa} 760 torr=101325 N⋅m−2760 \text{ torr} = 101325 \text{ N} \cdot \text{m}^{-2}

    The converted value is 101325 N⋅m−2\boxed{\text{101325 N} \cdot \text{m}^{-2}}.

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