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Convert the initial velocity from kilometers per hour to meters per second.

Physics

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Answer

2 m/s2\text{2 m/s}^2

Step-by-step solution

4 steps

  1. Convert the initial velocity from kilometers per hour to meters per second.

    u=72 km/hr×1000 m1 km×1 hr3600 su = 72 \text{ km/hr} \times \frac{1000 \text{ m}}{1 \text{ km}} \times \frac{1 \text{ hr}}{3600 \text{ s}} u=72×10003600 m/su = \frac{72 \times 1000}{3600} \text{ m/s} u=720003600 m/su = \frac{72000}{3600} \text{ m/s} u=20 m/su = 20 \text{ m/s}

  2. Identify the final velocity and time.

    The bus is brought to rest, so the final velocity v=0 m/sv = 0 \text{ m/s}.
    The time taken is t=10 st = 10 \text{ s}.

  3. Use the first equation of motion to find the acceleration.

    The formula is v=u+atv = u + at.
    Rearrange to solve for aa:

    a=v−uta = \frac{v - u}{t}

    Substitute the values:

    a=0 m/s−20 m/s10 sa = \frac{0 \text{ m/s} - 20 \text{ m/s}}{10 \text{ s}} a=−20 m/s10 sa = \frac{-20 \text{ m/s}}{10 \text{ s}} a=−2 m/s2a = -2 \text{ m/s}^2

  4. State the deceleration.

    Deceleration is the magnitude of the negative acceleration.
    Deceleration =∣a∣=∣−2 m/s2∣=2 m/s2= |a| = |-2 \text{ m/s}^2| = 2 \text{ m/s}^2.

    The deceleration/retardation of the bus is 2 m/s2\text{2 m/s}^2.

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