This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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b) The critical angle is the angle of incidence in the optically denser medium for which the angle of refraction in the optically rarer medium is 90^. c) Step 1: Identify the given values. The refractive index of glass, n_glass = 1.48. The refractive index of air, n_air = 1.00. From the diagram, the ray is incident at point X on the glass-air interface. The refracted ray travels along the interface, meaning the angle of refraction in air is r = 90^. The angle 'i' is the angle of incidence in the glass. Step 2: Apply Snell's Law for the critical angle. When light travels from a denser medium (glass) to a rarer medium (air) and the angle of refraction is 90^, the angle of incidence is the critical angle. Snell's Law: n_glass i = n_air r Step 3: Substitute the values and solve for i. 1.48 × i = 1.00 × 90^ Since 90^ = 1: 1.48 × i = 1.00 × 1 i = (1.00)/(1.48) i = 0.67567 i = (0.67567) i = 42.5^ Angle i is 42.5^. d) Two applications of total internal reflection are: • Optical fibers for transmitting data (e.g., internet, medical imaging). • Periscopes and binoculars use prisms to reflect light without significant loss of intensity. 3 done, 2 left today. You're making progress.