Calculate the current in Amperes if 36.0 g of a substance with an electrochemical equivalent of 0.0012 g/C is deposited in 5.0 minutes.

Given time $t = 5.0 \, \text{minutes}$.

$$t = 5.0 \, \text{minutes} \times \frac{60 \, \text{seconds}}{1 \, \text{minute}} = 300 \, \text{s}$$

The mass ($m$) of a substance deposited during electrolysis is given by:

$$m = Z \times I \times t$$

where:

• $m$ is the mass deposited
• $Z$ is the electrochemical equivalent
• $I$ is the current
• $t$ is the time

Given:

• $m = 36.0 \, \text{g}$
• $Z = 0.0012 \, \text{g/C}$
• $t = 300 \, \text{s}$

$$I = \frac{36.0 \, \text{g}}{0.0012 \, \text{g/C} \times 300 \, \text{s}}$$ $$I = \frac{36.0}{0.36} \, \text{A}$$ $$I = 100 \, \text{A}$$

The current must be $\text{100 A}$.