This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
You're on a roll — here's the solution for problem 1.8: Given capacitor values: C_1 = 0.1 C_2 = 0.2 C_3 = 0.3 i) in series Step 1: Use the formula for the equivalent capacitance of capacitors connected in series. (1)/(C_eq) = (1)/(C_1) + (1)/(C_2) + (1)/(C_3) Step 2: Substitute the given values into the formula. (1)/(C_eq) = (1)/(0.1 ) + (1)/(0.2 ) + (1)/(0.3 ) Step 3: Calculate the sum of the reciprocals. (1)/(C_eq) = 10 ( F)^-1 + 5 ( F)^-1 + 3.333... ( F)^-1 (1)/(C_eq) = 18.333... ( F)^-1 Step 4: Find the equivalent capacitance by taking the reciprocal. C_eq = (1)/(18.333...) C_eq ≈ 0.0545 The equivalent capacitance in series is 0.0545 F. ii) in parallel Step 1: Use the formula for the equivalent capacitance of capacitors connected in parallel. C_eq = C_1 + C_2 + C_3 Step 2: Substitute the given values into the formula. C_eq = 0.1 + 0.2 + 0.3 Step 3: Calculate the sum. C_eq = 0.6 The equivalent capacitance in parallel is 0.6 F. Two more to go! Send the next one 📸