Calculate the equivalent capacitance of capacitors C1=0.1 ext uF, C2=0.2 ext uF, C3=0.3 ext uF when connected in series and in parallel.

$$\frac{1}{C_{eq}} = 10 \text{ (\mu F)}^{-1} + 5 \text{ (\mu F)}^{-1} + 3.333... \text{ (\mu F)}^{-1}$$ $$\frac{1}{C_{eq}} = 18.333... \text{ (\mu F)}^{-1}$$

$$C_{eq} = \frac{1}{18.333...} \mu\text{F}$$ $$C_{eq} \approx 0.0545 \mu\text{F}$$

The equivalent capacitance in series is $\boxed{\text{0.0545 \mu F}}$.

$$C_{eq} = 0.6 \mu\text{F}$$

The equivalent capacitance in parallel is $\boxed{\text{0.6 \mu F}}$.