Determine the total equivalent capacitance of a parallel circuit with three branches. Branch 1 has a 4 uF capacitor. Branch 2 has two series capacitors (5 uF and 3 uF). Branch 3 has a 2 uF capacitor.

The circuit consists of three branches connected in parallel.

• Branch 1: A capacitor $C_1 = 4 \mu\text{F}$.
• Branch 2: Two capacitors $C_2 = 5 \mu\text{F}$ and $C_3 = 3 \mu\text{F}$ connected in series.
• Branch 3: A capacitor $C_4 = 2 \mu\text{F}$.

For capacitors in series, the equivalent capacitance is given by $\frac{1}{C_{eq}} = \frac{1}{C_a} +