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Explain how fish survive in frozen ponds and define pitch of a micrometer screw gauge with calculation of observed reading.

Physics

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Answer

0.5 mm\text{0.5 mm}

1.073 cm\text{1.073 cm}

Step-by-step solution

4 steps
  1. Answer Question 1.

    Fish can survive under frozen pond surfaces due to the anomalous expansion of water. Water is densest at 4∘C4^\circ \text{C}. As the surface of a pond freezes, the colder, less dense water (0∘C0^\circ \text{C} to 4∘C4^\circ \text{C}) remains at the top, eventually freezing. The denser water at 4∘C4^\circ \text{C} sinks to the bottom, forming a layer of liquid water where fish can survive.

  2. Answer Question 2i.

    The pitch of a micrometer screw gauge is the distance moved by the spindle for one complete rotation of the thimble. A standard micrometer with 50 divisions on the thimble typically has a pitch of 0.5mm0.5 \text{mm}.

    The pitch of the gauge is 0.5 mm\boxed{\text{0.5 mm}}.

  3. Answer Question 2ii.

    First, determine the observed reading from the micrometer scale.
    Main scale reading: The last visible mark on the main scale is 10mm10 \text{mm}. The 0.5mm0.5 \text{mm} mark after 10mm10 \text{mm} is also visible.
    Main scale reading =10.5mm= 10.5 \text{mm}.

    Thimble scale reading: The line on the main scale aligns with the 37th37^\text{th} division on the thimble scale.
    Thimble scale reading =37= 37.

    Least count of the micrometer:

    Least Count=PitchNumber of divisions on thimble=0.5mm50=0.01mm\text{Least Count} = \frac{\text{Pitch}}{\text{Number of divisions on thimble}} = \frac{0.5 \text{mm}}{50} = 0.01 \text{mm}

    Observed reading:

    Observed Reading=Main Scale Reading+(Thimble Scale Reading×Least Count)\text{Observed Reading} = \text{Main Scale Reading} + (\text{Thimble Scale Reading} \times \text{Least Count}) Observed Reading=10.5mm+(37×0.01mm)\text{Observed Reading} = 10.5 \text{mm} + (37 \times 0.01 \text{mm}) Observed Reading=10.5mm+0.37mm=10.87mm\text{Observed Reading} = 10.5 \text{mm} + 0.37 \text{mm} = 10.87 \text{mm}

    Given positive error:

    Zero Error=+0.014cm=+0.14mm\text{Zero Error} = +0.014 \text{cm} = +0.14 \text{mm}

    Correct reading:

    Correct Reading=Observed Reading−Zero Error\text{Correct Reading} = \text{Observed Reading} - \text{Zero Error} Correct Reading=10.87mm−0.14mm\text{Correct Reading} = 10.87 \text{mm} - 0.14 \text{mm} Correct Reading=10.73mm\text{Correct Reading} = 10.73 \text{mm}

    Converting to centimeters:

    Correct Reading=10.73mm×1cm10mm=1.073cm\text{Correct Reading} = 10.73 \text{mm} \times \frac{1 \text{cm}}{10 \text{mm}} = 1.073 \text{cm}

    The correct reading on the scale is 1.073 cm\boxed{\text{1.073 cm}}.

  4. Answer Question 3.

    When liquid soap is introduced into the water drop, the surface tension of the water decreases. Surface tension is responsible for holding the water drop in a spherical shape. With reduced surface tension, the cohesive forces within the drop become weaker, causing the drop to spread out and become flatter on the surface.

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