This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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Alright — let's do this. Here are the solutions to the multiple-choice questions: 1. A frequency of 2 MHz has time period of The relationship between frequency (f) and time period (T) is T = (1)/(f). Given f = 2 MHz = 2 × 10^6 Hz. T = (1)/(2 × 10^6 Hz) = 0.5 × 10^-6 s = 0.5 µs Answer: a) 0.5 µsec 2. The 120 Volts r.m.s. has peak value of For a sine wave, the peak voltage (V_peak) is related to the RMS voltage (V_rms) by V_peak = V_rms × sqrt(2). Given V_rms = 120 V. V_peak = 120 V × sqrt(2) ≈ 120 V × 1.414 ≈ 169.68 V This is approximately 170 V. Answer: b) 170 Volts 3. If the capacitance is doubled the capacitive reactance is Capacitive reactance (X_C) is given by the formula X_C = (1)/(2 f C). If capacitance C is doubled to 2C, the new capacitive reactance X_C' will be: X_C' = (1)/(2 f (2C)) = (1)/(2) ((1)/(2 f C)) = (1)/(2) X_C Therefore, the capacitive reactance is halved. Answer: a) Halved 4. Two 5000 inductive reactance are in parallel have an equivalent reactance of For two parallel reactances X_L1 and X_L2, the equivalent reactance X_eq is given by: (1)/(X_eq) = (1)/(X_L1) + (1)/(X_L2) Given X_L1 = 5000 and X_L2 = 5000 . (1)/(X_eq) = (1)/(5000 ) + (1)/(5000 ) = (2)/(5000 ) X_eq = 5000 2 = 2500 Answer: a) 2500 5. In a sine wave ac circuit the voltage across a capacitance In a purely capacitive AC circuit, the current leads the voltage by 90^. Conversely, the voltage across the capacitance lags the current by 90^. Answer: a) Lags current by 90^ 6. Alternating current can induce voltage because alternating current has a According to Faraday's Law of Induction, a voltage is induced when there is a change in magnetic flux. Alternating current continuously changes its magnitude and direction, which produces a continuously varying magnetic flux. Answer: b) Varying magnetic flux 7. An iron core transformer with a 1:8 step up ratio has 120 V applied across the primary. The voltage across the secondary equals For an ideal transformer, the ratio of secondary voltage (V_s) to primary voltage (V_p) is equal to the ratio of secondary turns (N_s) to primary turns (N_p): (V_s)/(V_p) = (N_s)/(N_p) Given turns ratio N_p : N_s = 1:8, so (N_s)/(N_p) = (8)/(1). Given primary voltage V_p = 120 V. (V_s)/(120 V) = (8)/(1) V_s = 120 V × 8 = 960 V Answer: d) 960V 8. When capacitance is increased the resonant frequency of the LC circuit The resonant frequency (f_r) of an LC circuit is given by the formula: f_r = (1)/(2(LC)) From the formula, f_r is inversely proportional to the square root of the capacitance (C). If C increases, f_r will decrease. Answer: b) Decreases Send me the next one 📸