Step 1: Write the formula for equivalent resistance of resistors in parallel. For $n$ resistors connected in parallel, the equivalent resistance $R_{eq}$ is given by: $$ \frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \dots + \frac{1}{R_n} $$ Step 2: Substitute the given values into the formula. We have three resistors, each with a resistance of $2 \, \Omega$. So, $R_1 = R_2 = R_3 = 2 \, \Omega$. $$ \frac{1}{R_{eq}} = \frac{1}{2 \, \Omega} + \frac{1}{2 \, \Omega} + \frac{1}{2 \, \Omega} $$ Step 3: Calculate the sum of the reciprocals. $$ \frac{1}{R_{eq}} = \frac{1+1+1}{2 \, \Omega} = \frac{3}{2 \, \Omega} $$ Step 4: Calculate $R_{eq}$. $$ R_{eq} = \frac{2 \, \Omega}{3} $$ $$ R_{eq} \approx 0.6666... \, \Omega $$ Rounding to two decimal places, $R_{eq} \approx 0.67 \, \Omega$. Step 5: Compare with the given options. The calculated value matches option A. The final answer is $\boxed{\text{A. } 0.67 \, \Omega}$. Send me the next one 📸