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Record the weight of the wooden block shown in Fig. 3.1. (b) Calculate the mass of the wooden block. (g = 10N/kg) The wooden block is raised to a vertical height of 10m. Calculate the gravitational potential energy gained by the b

Physics

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3 parts
a

2 N\text{2 N}

b

0.2 kg\text{0.2 kg}

c

20 J\text{20 J}

Step-by-step solution

6 steps

Here are the solutions to the problems:

Part a· 1 step

  1. Read the value from the spring balance in Fig 3.1.

    The spring balance has major markings at 0 N, 5 N, and 10 N. Between 0 N and 5 N, there are 4 smaller tick marks, dividing the 5 N range into 5 equal intervals. Therefore, each small interval represents 5 N5=1 N\frac{5 \text{ N}}{5} = 1 \text{ N}. The pointer is at the second tick mark after 0 N.
    The weight of the wooden block is 0 N+2×1 N=2 N0 \text{ N} + 2 \times 1 \text{ N} = 2 \text{ N}.
    The weight of the wooden block is 2 N\boxed{\text{2 N}}.

Part b

0.2 kg\text{0.2 kg}

  1. State the formula for weight.

    The relationship between weight (WW), mass (mm), and acceleration due to gravity (gg) is given by:

    W=mgW = mg
  2. Rearrange the formula to solve for mass.

    m=Wgm = \frac{W}{g}
  3. Substitute the given values and calculate the mass.

    Given W=2 NW = 2 \text{ N} (from part a) and g=10 N/kgg = 10 \text{ N/kg}.

    m=2 N10 N/kgm = \frac{2 \text{ N}}{10 \text{ N/kg}} m=0.2 kgm = 0.2 \text{ kg}

    The mass of the wooden block is 0.2 kg\boxed{\text{0.2 kg}}.

Part c

20 J\text{20 J}

  1. State the formula for gravitational potential energy.

    The gravitational potential energy (GPEGPE) gained is given by:

    GPE=mghGPE = mgh
  2. Substitute the values and calculate the gravitational potential energy.

    Given m=0.2 kgm = 0.2 \text{ kg} (from part b), g=10 N/kgg = 10 \text{ N/kg}, and h=10 mh = 10 \text{ m}.

    GPE=(0.2 kg)×(10 N/kg)×(10 m)GPE = (0.2 \text{ kg}) \times (10 \text{ N/kg}) \times (10 \text{ m}) GPE=2 N×10 mGPE = 2 \text{ N} \times 10 \text{ m} GPE=20 JGPE = 20 \text{ J}

    The gravitational potential energy gained by the block is 20 J\boxed{\text{20 J}}.

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