Given time for energy transfer from A to B, which is the period, T = 2.5 x 10⁻³ s.

Physics

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Answer

c) 4.0×102 Hz\text{c) } 4.0 \times 10^{2} \text{ Hz}

Step-by-step solution

4 steps

To solve question 16, we need to calculate the frequency of the wave.

  1. Identify the given information.

    The diagram shows one complete wave cycle from point A (a crest) to point B (the next crest). The time taken for this complete cycle is the period (TT) of the wave.
    Given time for energy transfer from A to B, which is the period, T=2.5×10−3T = 2.5 \times 10^{-3} s.

  2. Use the formula for frequency.

    Frequency (ff) is the reciprocal of the period (TT).

    f=1Tf = \frac{1}{T}
  3. Substitute the value of the period and calculate the frequency.

    f=12.5×10−3 sf = \frac{1}{2.5 \times 10^{-3} \text{ s}} f=12.5×103 Hzf = \frac{1}{2.5} \times 10^{3} \text{ Hz} f=0.4×103 Hzf = 0.4 \times 10^{3} \text{ Hz} f=400 Hzf = 400 \text{ Hz}

    This can also be written in scientific notation as 4.0×1024.0 \times 10^{2} Hz.

  4. Compare with the given options.

    The calculated frequency is 4.0×1024.0 \times 10^{2} Hz, which corresponds to option (c).

    The final answer is c) 4.0×102 Hz\text{c) } 4.0 \times 10^{2} \text{ Hz}.

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