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What happens to the heat supplied at points where there is no increase in temperature?

Physics

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2 parts
b

40 m/s\text{40 m/s}

c

0.025 s\text{0.025 s}

Step-by-step solution

3 steps

Part a

Amplitude is the maximum displacement of a point on a wave or vibrating body from its equilibrium position.

Part b

40 m/s\text{40 m/s}

  1. Determine the wavelength (λ\lambda) from Figure B5.1.

    The figure shows that a distance of 1.5 m1.5 \text{ m} corresponds to 1.5 complete wavelengths.

    1.5λ=1.5 m1.5 \lambda = 1.5 \text{ m} λ=1.5 m1.5=1 m\lambda = \frac{1.5 \text{ m}}{1.5} = 1 \text{ m}
  2. Calculate the speed of the wave (vv) using the formula v=fλv = f \lambda.

    Given frequency f=40 Hzf = 40 \text{ Hz}.

    v=(40 Hz)×(1 m)v = (40 \text{ Hz}) \times (1 \text{ m}) v=40 m/sv = 40 \text{ m/s}

    The speed of the wave is 40 m/s\boxed{\text{40 m/s}}.

Part c

0.025 s\text{0.025 s}

  1. Calculate the period (TT) of the wave using the formula T=1fT = \frac{1}{f}.

    Given frequency f=40 Hzf = 40 \text{ Hz}.

    T=140 HzT = \frac{1}{40 \text{ Hz}} T=0.025 sT = 0.025 \text{ s}

    The period of the wave is 0.025 s\boxed{\text{0.025 s}}.

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