This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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Here are the solutions to the questions. c) (i) Name the symbols labelled II, III and IV. II: Resistor* III: Switch* IV: Voltmeter* (ii) Draw a circuit diagram using all the symbols labelled I, II, III, IV and V. A circuit diagram should be drawn with the following components: A cell (I) connected in series with a switch (III), a resistor (II), and an ammeter (V). A voltmeter (IV) connected in parallel across the resistor (II). (iii) If the circuit is closed and V reads 5 units with IV reading 15 units, determine the value of II in S.I. units. Step 1: Identify the given values. The reading of V (ammeter) is the current, I = 5 A. The reading of IV (voltmeter) is the potential difference, V = 15 V. The component II is a resistor, R. Step 2: Apply Ohm's Law. Ohm's Law states that V = IR. Step 3: Calculate the resistance. R = (V)/(I) R = 15 V5 A R = 3 The value of II is 3 . d) (i) Identify the solution that would have a pH value equal to: (α) 7; C* (NaCl is a neutral salt) (β) 14. E* (NaOH is a strong base, which would have a very high pH) (ii) Identify the solution that can be classified as a/an: (α) strong acid; A* (HCl is a strong acid) (β) neutral; C* (NaCl is a neutral salt) (γ) weak base. D* (NH₃ is a weak base) (iii) Suggest the pH value of solution A. Solution A is 0.1 mol dm⁻³ HCl. Since HCl is a strong acid, it fully dissociates in water. Step 1: Determine the hydrogen ion concentration. For 0.1 mol dm⁻³ HCl, [H^+] = 0.1 mol dm^-3. Step 2: Calculate the pH. pH = -[H^+] pH = -(0.1) pH = 1 The suggested pH value of solution A is 1. (iv) Identify two solutions in the table that will react to form salt and water. This describes a neutralization reaction between an acid and a base. Acids in the table: A (HCl), B (CH₃COOH) Bases in the table: D (NH₃), E (NaOH) Two solutions that will react to form salt and water are A and E (HCl and NaOH) or A and D (HCl and NH₃) or B and E (CH₃COOH and NaOH) or B and D (CH₃COOH and NH₃). (v) What would be the colour of solution C upon addition of drops of universal indicator. Solution C is 0.1 mol dm⁻³ NaCl. Sodium chloride is a salt formed from a strong acid (HCl) and a strong base (NaOH), making it a neutral solution. Universal indicator turns green in a neutral solution (pH 7). That's 2 down. 3 left today — send the next one.