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Identify the given initial pressure and temperatures.

Physics

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Answer

60.5 mmHg\text{60.5 mmHg}

Step-by-step solution

4 steps

To calculate the pressure exerted by the gas:

  1. Identify the given initial pressure and temperatures.

    P1=50 mmHgP_1 = 50 \text{ mmHg} T1=27∘CT_1 = 27^\circ\text{C} T2=90∘CT_2 = 90^\circ\text{C}
  2. Convert the temperatures from Celsius to Kelvin.

    T1=27∘C+273=300 KT_1 = 27^\circ\text{C} + 273 = 300 \text{ K} T2=90∘C+273=363 KT_2 = 90^\circ\text{C} + 273 = 363 \text{ K}
  3. Since the volume is maintained at constant, use the Pressure Law (Gay-Lussac's Law), which states that P1T1=P2T2\frac{P_1}{T_1} = \frac{P_2}{T_2}.

    Rearrange the formula to solve for P2P_2.

    P2=P1×T2T1P_2 = P_1 \times \frac{T_2}{T_1}
  4. Substitute the values and calculate the final pressure.

    P2=50 mmHg×363 K300 KP_2 = 50 \text{ mmHg} \times \frac{363 \text{ K}}{300 \text{ K}} P2=50×1.21 mmHgP_2 = 50 \times 1.21 \text{ mmHg} P2=60.5 mmHgP_2 = 60.5 \text{ mmHg}

    The pressure exerted by the gas is 60.5 mmHg\text{60.5 mmHg}.

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