In step 1, how did u know that r=......

Physics

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Answer

You're asking about the derivation of r=2Lsin⁡θr = 2L \sin \theta.

Step-by-step solution

4 steps

Here's how we get that:

  1. Visualize the setup.

    Imagine the suspension point at the top, and the two threads hanging down, each attached to a ball. The angle between the two threads is given as 60∘60^\circ.

  2. Consider the geometry.

    If you draw a vertical line straight down from the suspension point, it will bisect the angle between the threads and also bisect the distance between the two balls.
    This creates two identical right-angled triangles.

    • The hypotenuse of each right-angled triangle is the length of the thread, LL.
    • The angle between the thread and the vertical line is θ\theta. Since the total angle between the threads is 60∘60^\circ, then θ=60∘2=30∘\theta = \frac{60^\circ}{2} = 30^\circ.
    • The side opposite to this angle θ\theta is half the distance between the balls. Let's call this half-distance xx.
  3. Apply trigonometry.

    In a right-angled triangle, the sine of an angle is the ratio of the length of the opposite side to the length of the hypotenuse:

    sin⁡θ=oppositehypotenuse\sin \theta = \frac{\text{opposite}}{\text{hypotenuse}} sin⁡θ=xL\sin \theta = \frac{x}{L}

    Solving for xx:

    x=Lsin⁡θx = L \sin \theta
  4. Relate xx to rr.

    The total distance rr between the two balls is twice this half-distance xx:

    r=2xr = 2x

    Substituting the expression for xx:

    r=2Lsin⁡θr = 2L \sin \theta

    In the problem, L=0.100 mL = 0.100 \text{ m} and θ=30∘\theta = 30^\circ.

    r=2×0.100 m×sin⁡(30∘)r = 2 \times 0.100 \text{ m} \times \sin(30^\circ) r=2×0.100 m×0.5r = 2 \times 0.100 \text{ m} \times 0.5 r=0.100 mr = 0.100 \text{ m}
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