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Define neutral atom, element, molecule. 2. Give 3 examples of element, molecule. 3. State the bond found in ZnO, Al2O3, CaCl2. 4. With a diagram, explain the formation of BeCl2.

Chemistry

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3 parts
a

[Na]+ [ : ⁣Cl¨ ⁣: ]−[\mathrm{Na}]^{+} \ [\ :\!\ddot{\mathrm{Cl}}\!:\ ]^{-}

b

[Mg]2+ [ : ⁣O¨ ⁣: ]2−[\mathrm{Mg}]^{2+} \ [\ :\!\ddot{\mathrm{O}}\!:\ ]^{2-}

c

[Ca]2+ 2[ : ⁣F¨ ⁣: ]−[\mathrm{Ca}]^{2+} \ 2[\ :\!\ddot{\mathrm{F}}\!:\ ]^{-}

Step-by-step solution

9 steps

Part a· 3 steps

NaCl

  1. Lewis dot symbols of atoms.

    Sodium (Group 1): 1 valence electron.

    Na⋅\mathrm{Na \cdot}

    Chlorine (Group 17): 7 valence electrons.

    ⋅Cl¨⋅\cdot \ddot{\mathrm{Cl}} \cdot
  2. Electron transfer for octet stability.

    Na loses 1 electron to Cl (Na achieves He configuration, Cl achieves octet).

    Na⋅+⋅Cl¨⋅ ⟶ [Na]++[ : ⁣Cl¨ ⁣: ]−\mathrm{Na \cdot} + \cdot \ddot{\mathrm{Cl}} \cdot \ \longrightarrow \ [\mathrm{Na}]^{+} + [\ :\!\ddot{\mathrm{Cl}}\!:\ ]^{-}
  3. Ionic bond formation.

    Oppositely charged ions [Na]+[\mathrm{Na}]^{+} and [ : ⁣Cl¨ ⁣: ]−[\ :\!\ddot{\mathrm{Cl}}\!:\ ]^{-} are held by electrostatic attraction.

    Final Lewis dot diagram:
    [Na]^{+} \ [\ :!\ddot{Cl}!:\ ]^{-}

Part b

[Mg]2+ [ : ⁣O¨ ⁣: ]2−[\mathrm{Mg}]^{2+} \ [\ :\!\ddot{\mathrm{O}}\!:\ ]^{2-}

MgO

  1. Lewis dot symbols of atoms.

    Magnesium (Group 2): 2 valence electrons.

    ⋅Mg⋅\cdot \mathrm{Mg} \cdot

    Oxygen (Group 16): 6 valence electrons.

    ⋅O¨⋅\cdot \ddot{\mathrm{O}} \cdot
  2. Electron transfer for octet stability.

    Mg loses 2 electrons to O (Mg achieves Ne configuration, O achieves octet).

    ⋅Mg⋅+⋅O¨⋅ ⟶ [Mg]2++[ : ⁣O¨ ⁣: ]2−\cdot \mathrm{Mg} \cdot + \cdot \ddot{\mathrm{O}} \cdot \ \longrightarrow \ [\mathrm{Mg}]^{2+} + [\ :\!\ddot{\mathrm{O}}\!:\ ]^{2-}
  3. Ionic bond formation.

    Oppositely charged ions [Mg]2+[\mathrm{Mg}]^{2+} and [ : ⁣O¨ ⁣: ]2−[\ :\!\ddot{\mathrm{O}}\!:\ ]^{2-} are held by electrostatic attraction.

    Final Lewis dot diagram:
    [Mg]^{2+} \ [\ :!\ddot{O}!:\ ]^{2-}

Part c

[Ca]2+ 2[ : ⁣F¨ ⁣: ]−[\mathrm{Ca}]^{2+} \ 2[\ :\!\ddot{\mathrm{F}}\!:\ ]^{-}

CaF₂

  1. Lewis dot symbols of atoms.

    Calcium (Group 2): 2 valence electrons.

    ⋅Ca⋅\cdot \mathrm{Ca} \cdot

    Fluorine (Group 17): 7 valence electrons (×2).

    ⋅F¨⋅\cdot \ddot{\mathrm{F}} \cdot
  2. Electron transfer for octet stability.

    Ca loses 2 electrons (1 to each F). Ca achieves Ar configuration, each F achieves octet.

    ⋅Ca⋅+2(⋅F¨⋅) ⟶ [Ca]2++2[ : ⁣F¨ ⁣: ]−\cdot \mathrm{Ca} \cdot + 2(\cdot \ddot{\mathrm{F}} \cdot) \ \longrightarrow \ [\mathrm{Ca}]^{2+} + 2[\ :\!\ddot{\mathrm{F}}\!:\ ]^{-}
  3. Ionic bond formation.

    Oppositely charged ions [Ca]2+[\mathrm{Ca}]^{2+} and 2[ : ⁣F¨ ⁣: ]−2[\ :\!\ddot{\mathrm{F}}\!:\ ]^{-} are held by electrostatic attraction.

    Final Lewis dot diagram:
    [Ca]^{2+} \ 2[\ :!\ddot{F}!:\ ]^{-}

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