This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
Define neutral atom, element, molecule. 2. Give 3 examples of element, molecule. 3. State the bond found in ZnO, Al2O3, CaCl2. 4. With a diagram, explain the formation of BeCl2.

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Answer
(a) NaCl
Step 1: Lewis dot symbols of atoms.
Sodium (Group 1): 1 valence electron.
Chlorine (Group 17): 7 valence electrons.
Step 2: Electron transfer for octet stability.
Na loses 1 electron to Cl (Na achieves He configuration, Cl achieves octet).
Step 3: Ionic bond formation.
Oppositely charged ions and are held by electrostatic attraction.
Final Lewis dot diagram:
[\mathrm{Na]^{+} \ [\ :!\ddot{Cl}!:\ ]^{-}}
(b) MgO
Step 1: Lewis dot symbols of atoms.
Magnesium (Group 2): 2 valence electrons.
Oxygen (Group 16): 6 valence electrons.
Step 2: Electron transfer for octet stability.
Mg loses 2 electrons to O (Mg achieves Ne configuration, O achieves octet).
Step 3: Ionic bond formation.
Oppositely charged ions and are held by electrostatic attraction.
Final Lewis dot diagram:
[\mathrm{Mg]^{2+} \ [\ :!\ddot{O}!:\ ]^{2-}}
(c) CaF₂
Step 1: Lewis dot symbols of atoms.
Calcium (Group 2): 2 valence electrons.
Fluorine (Group 17): 7 valence electrons (×2).
Step 2: Electron transfer for octet stability.
Ca loses 2 electrons (1 to each F). Ca achieves Ar configuration, each F achieves octet.
Step 3: Ionic bond formation.
Oppositely charged ions and are held by electrostatic attraction.
Final Lewis dot diagram:
[\mathrm{Ca]^{2+} \ 2[\ :!\ddot{F}!:\ ]^{-}}
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(a) NaCl Step 1: Lewis dot symbols of atoms. Sodium (Group 1): 1 valence electron.