Define neutral atom, element, molecule. 2. Give 3 examples of element, molecule. 3. State the bond found in ZnO, Al2O3, CaCl2. 4. With a diagram, explain the formation of BeCl2.

Chemistry
Define neutral atom, element, molecule. 2. Give 3 examples of element, molecule. 3. State the bond found in ZnO, Al2O3, CaCl2. 4. With a diagram, explain the formation of BeCl2.

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Answer

[Na]+ [ : ⁣Cl¨ ⁣: ][Na]^{+} \ [\ :\!\ddot{Cl}\!:\ ]^{-}

(a) NaCl

Step 1: Lewis dot symbols of atoms.
Sodium (Group 1): 1 valence electron.
NaNa \cdot
Chlorine (Group 17): 7 valence electrons.
Cl¨\cdot \ddot{Cl} \cdot

Step 2: Electron transfer for octet stability.
Na loses 1 electron to Cl (Na achieves He configuration, Cl achieves octet).
Na+Cl¨  [Na]++[ : ⁣Cl¨ ⁣: ]Na \cdot + \cdot \ddot{Cl} \cdot \ \longrightarrow \ [Na]^{+} + [\ :\!\ddot{Cl}\!:\ ]^{-}

Step 3: Ionic bond formation.
Oppositely charged ions [Na]+[Na]^{+} and [ : ⁣Cl¨ ⁣: ][\ :\!\ddot{Cl}\!:\ ]^{-} are held by electrostatic attraction.

Final Lewis dot diagram:
[\mathrm{Na]^{+} \ [\ :!\ddot{Cl}!:\ ]^{-}}

(b) MgO

Step 1: Lewis dot symbols of atoms.
Magnesium (Group 2): 2 valence electrons.
Mg\cdot Mg \cdot
Oxygen (Group 16): 6 valence electrons.
O¨\cdot \ddot{O} \cdot

Step 2: Electron transfer for octet stability.
Mg loses 2 electrons to O (Mg achieves Ne configuration, O achieves octet).
Mg+O¨  [Mg]2++[ : ⁣O¨ ⁣: ]2\cdot Mg \cdot + \cdot \ddot{O} \cdot \ \longrightarrow \ [Mg]^{2+} + [\ :\!\ddot{O}\!:\ ]^{2-}

Step 3: Ionic bond formation.
Oppositely charged ions [Mg]2+[Mg]^{2+} and [ : ⁣O¨ ⁣: ]2[\ :\!\ddot{O}\!:\ ]^{2-} are held by electrostatic attraction.

Final Lewis dot diagram:
[\mathrm{Mg]^{2+} \ [\ :!\ddot{O}!:\ ]^{2-}}

(c) CaF₂

Step 1: Lewis dot symbols of atoms.
Calcium (Group 2): 2 valence electrons.
Ca\cdot Ca \cdot
Fluorine (Group 17): 7 valence electrons (×2).
F¨\cdot \ddot{F} \cdot

Step 2: Electron transfer for octet stability.
Ca loses 2 electrons (1 to each F). Ca achieves Ar configuration, each F achieves octet.
Ca+2(F¨)  [Ca]2++2[ : ⁣F¨ ⁣: ]\cdot Ca \cdot + 2(\cdot \ddot{F} \cdot) \ \longrightarrow \ [Ca]^{2+} + 2[\ :\!\ddot{F}\!:\ ]^{-}

Step 3: Ionic bond formation.
Oppositely charged ions [Ca]2+[Ca]^{2+} and 2[ : ⁣F¨ ⁣: ]2[\ :\!\ddot{F}\!:\ ]^{-} are held by electrostatic attraction.

Final Lewis dot diagram:
[\mathrm{Ca]^{2+} \ 2[\ :!\ddot{F}!:\ ]^{-}}

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Quick Answer

(a) NaCl Step 1: Lewis dot symbols of atoms. Sodium (Group 1): 1 valence electron.

Define neutral atom, element, molecule. 2. Give 3 examples of element, molecule. 3. State the bond found in ZnO, Al2O3, CaCl2. 4. With a diagram, explain the formation of BeCl2.
Chemistry

This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

ScanSolve AI Answer
(a) NaCl Step 1: Lewis dot symbols of atoms. Sodium (Group 1): 1 valence electron. Na · Chlorine (Group 17): 7 valence electrons. · Cl · Step 2: Electron transfer for octet stability. Na loses 1 electron to Cl (Na achieves He configuration, Cl achieves octet). Na · + · Cl · \ \ [Na]^+ + [\ :\!Cl\!:\ ]^- Step 3: Ionic bond formation. Oppositely charged ions [Na]^+ and [\ :\!Cl\!:\ ]^- are held by electrostatic attraction. Final Lewis dot diagram: [Na]^+ \ [\ :\!Cl\!:\ ]^- (b) MgO Step 1: Lewis dot symbols of atoms. Magnesium (Group 2): 2 valence electrons. · Mg · Oxygen (Group 16): 6 valence electrons. · O · Step 2: Electron transfer for octet stability. Mg loses 2 electrons to O (Mg achieves Ne configuration, O achieves octet). · Mg · + · O · \ \ [Mg]^2+ + [\ :\!O\!:\ ]^2- Step 3: Ionic bond formation. Oppositely charged ions [Mg]^2+ and [\ :\!O\!:\ ]^2- are held by electrostatic attraction. Final Lewis dot diagram: [Mg]^2+ \ [\ :\!O\!:\ ]^2- (c) CaF₂ Step 1: Lewis dot symbols of atoms. Calcium (Group 2): 2 valence electrons. · Ca · Fluorine (Group 17): 7 valence electrons (×2). · F · Step 2: Electron transfer for octet stability. Ca loses 2 electrons (1 to each F). Ca achieves Ar configuration, each F achieves octet. · Ca · + 2(· F ·) \ \ [Ca]^2+ + 2[\ :\!F\!:\ ]^- Step 3: Ionic bond formation. Oppositely charged ions [Ca]^2+ and 2[\ :\!F\!:\ ]^- are held by electrostatic attraction. Final Lewis dot diagram: [Ca]^2+ \ 2[\ :\!F\!:\ ]^-