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Make the relation Fx = u(m2 v2 / 2g)

Physics

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Answer

u=2gFXwu = \sqrt{\frac{2gFX}{w}}

Step-by-step solution

4 steps

  1. Write down the given equation.

    FX=w(u22g)FX = w \left( \frac{u^2}{2g} \right)

  2. Multiply both sides by $2g$ to remove the denominator.

    FX⋅2g=w⋅u2FX \cdot 2g = w \cdot u^2 2gFX=wu22gFX = w u^2

  3. Divide both sides by ww to isolate u2u^2.

    2gFXw=u2\frac{2gFX}{w} = u^2

  4. Take the square root of both sides to solve for uu.

    u=2gFXwu = \sqrt{\frac{2gFX}{w}}

    The relation with uu as the subject is u=2gFXw\boxed{u = \sqrt{\frac{2gFX}{w}}}.

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