Calculate the number of U-235 nuclei in 1 kg of natural uranium and the cost of electricity produced from it, given specific fission energy and cost per kWh.

Here's the calculation for the given problem: Part (i): The number of U-235 nuclei contained in 1.00 kg of natural uranium Step 1: Calculate the mass of U-235 in 1.00 kg of natural uranium. The mass of natural uranium is 1.00 kg = 1000 g. Natural uranium contains 0.7\% Uranium-235. Mass of U-235 = 0.007 × 1000 g = 7 g Step 2: Calculate the number of moles of U-235. The molar mass of U-235 is approximately 235 g/mol. Number of moles of U-235 = Mass of U-235Molar mass of U-235 = 7 g235 g/mol Step 3: Calculate the number of U-235 nuclei. Using Avogadro's number (N_A = 6.022 × 10^23 mol^-1): Number of U-235 nuclei = ((7)/(235)) mol × 6.022 × 10^23 nuclei/mol Number of U-235 nuclei = 1.793787 × 10^22 nuclei Rounding to three significant figures: 1.79 × 10^22 nuclei Part (ii): The cost to be paid to an electricity company Step 1: Calculate the total energy released from the fission of all U-235 nuclei. Energy released per U-235 fission = 200 MeV. Total energy released (in MeV) = (Number of U-235 nuclei) × (Energy per fission) Total energy released (in MeV) = (1.793787 × 10^22) × (200 MeV) Total energy released (in MeV) = 3.587574 × 10^24 MeV Step 2: Convert the total energy from MeV to Joules. Using the conversion factor 1 MeV = 1.602 × 10^-13 J: Total energy released (in J) = (3.587574 × 10^24 MeV) × (1.602 × 10^-13 J/MeV) Total energy released (in J) = 5.747809 × 10^11 J Step 3: Convert the total energy from Joules to kilowatt-hours (kWh), where 1 unit = 1 kWh. Using the conversion factor 1 kWh = 3.6 × 10^6 J: Energy in kWh = 5.747809 × 10^11 J3.6 × 10^6 J/kWh Energy in kWh = 159661.36 kWh Step 4: Calculate the total cost. The cost of electrical energy is 60 frs per unit (kWh). Total cost = (Energy in kWh) × (Cost per kWh) Total cost = (159661.36 kWh) × (60 frs/kWh) Total cost = 9579681.6 frs Rounding to three significant figures: 9.58 × 10^6 frs