Calculate object and image distances for a concave mirror with a focal length of 15 cm, given the image is real, inverted, and magnified three times.

May 10, 2026Physics

ScanSolve AI Answer

May 10, 2026

Answer

$m = -\frac{V}{U} \implies -3 = -\frac{V}{U} \implies V = 3U$

Here are the solutions to the problems based on your notes:

: Finding Object and Image Distances

Given:

Magnification ( $m$ ) is such that $V = 3U$ (from $m = V/U = 3$ ).
Focal length ( $F$ ) = $15 \text{ cm}$ .

We will assume this is a concave mirror forming a real, inverted, and magnified image. For a real image, the magnification $m = -3$ . Therefore, $m = -\frac{V}{U} \implies -3 = -\frac{V}{U} \implies V = 3U$ . For a concave mirror, the focal length is negative, so $f = -15 \

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Quick Answer

Problem 1: Finding Object and Image Distances Given: Magnification (m) is such that V = 3U (from m = V/U = 3).

Asked on May 10, 2026Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

ScanSolve AI AnswerAnswered on May 10, 2026

Here are the solutions to the problems based on your notes: Problem 1: Finding Object and Image Distances Given: Magnification (m) is such that V = 3U (from m = V/U = 3). Focal length (F) = 15 cm. We will assume this is a concave mirror forming a real, inverted, and magnified image. For a real image, the magnification m = -3. Therefore, m = -(V)/(U) -3 = -(V)/(U) V = 3U. For a concave mirror, the focal length is negative, so $f = -15 \