This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Hey AUDREY, good to see you again. To calculate the output voltage V_o, we will follow these steps: Step 1: Calculate the base current I_B. Using Kirchhoff's Voltage Law (KVL) for the base-emitter loop: V_in = I_B R_B + V_BE Given V_in = 2.7 \, V, R_B = 10 \, k = 10 × 10^3 \, , and V_BE = 0.7 \, V. 2.7 \, V = I_B (10 × 10^3 \, ) + 0.7 \, V I_B (10 × 10^3 \, ) = 2.7 \, V - 0.7 \, V I_B (10 × 10^3 \, ) = 2.0 \, V I_B = 2.0 \, V10 × 10^3 \, I_B = 0.2 × 10^-3 \, A = 0.2 \, mA Step 2: Calculate the collector current I_C. The collector current is related to the base current by the current gain : I_C = I_B Given = 60. I_C = 60 × (0.2 × 10^-3 \, A) I_C = 12 × 10^-3 \, A = 12 \, mA Step 3: Calculate the output voltage V_o. The output voltage V_o is the collector-emitter voltage V_CE. Using KVL for the collector-emitter loop: V_CC = I_C R_C + V_o V_o = V_CC - I_C R_C Given V_CC = 4.5 \, V and R_C = 200 \, . V_o = 4.5 \, V - (12 × 10^-3 \, A) × (200 \, ) V_o = 4.5 \, V - 2.4 \, V V_o = 2.1 \, V The output voltage is 2.1 V. Send me the next one 📸