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Explain the phenomenon of beats in sound waves and how the human ear perceives them, including an example.

Physics

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Step-by-step solution

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  1. Define beats and beat frequency.

    Beats are produced when two sound waves of slightly different frequencies interfere. This interference causes a periodic variation in the amplitude of the resultant wave, which is perceived as a periodic rise and fall in loudness. The beat frequency (fbeatf_{beat}) is the absolute difference between the frequencies of the two interfering waves:

    fbeat=∣f1−f2∣f_{beat} = |f_1 - f_2|

    where f1f_1 and f2f_2 are the frequencies of the two sound waves.

  2. Explain the perception of beats by the human ear.

    The human ear can only distinguish individual beats when the rate of loudness variation is slow enough.

    • When the frequency difference (fbeatf_{beat}) is less than approximately 10 Hz, the loudness changes at a slow pace, allowing our ears to perceive a distinct, pulsing sound.
    • When the frequency difference (fbeatf_{beat}) is greater than 10 Hz, the loudness changes too rapidly. The individual pulses of loudness merge into a continuous sound, and our ears cannot distinguish them as separate beats. Instead, we perceive a rough or dissonant sound, or sometimes two distinct tones if the frequency difference is very large.
  3. Exemplify the concept.

    Consider two tuning forks:

    • If one tuning fork has a frequency of 440 Hz440 \text{ Hz} and another has 442 Hz442 \text{ Hz}, the beat frequency is fbeat=∣440 Hz−442 Hz∣=2 Hzf_{beat} = |440 \text{ Hz} - 442 \text{ Hz}| = 2 \text{ Hz}. Our ears can easily perceive these 2 beats per second as a clear pulsing sound.
    • If one tuning fork has a frequency of 440 Hz440 \text{ Hz} and another has 455 Hz455 \text{ Hz}, the beat frequency is fbeat=∣440 Hz−455 Hz∣=15 Hzf_{beat} = |440 \text{ Hz} - 455 \text{ Hz}| = 15 \text{ Hz}. In this case, the loudness changes 15 times per second, which is too fast for the human ear to distinguish as individual beats. We would hear a continuous, possibly rough, sound rather than distinct pulses.

    The final answer is It is difficult to recognize beats when the frequency difference is greater than 10 Hz because the loudness changes too rapidly for the human ear to distinguish individual pulses.\boxed{\text{It is difficult to recognize beats when the frequency difference is greater than 10 Hz because the loudness changes too rapidly for the human ear to distinguish individual pulses.}}

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