Problem 1: Resistors of 2 , 4 , and 6 are connected in series, and a voltage of 24 V is applied across them.

Here are the calculations for the given circuit: Problem 1: Resistors of 2 , 4 , and 6 are connected in series, and a voltage of 24 V is applied across them. i) Calculate the total resistance. Step 1: For resistors connected in series, the total resistance R_total is the sum of the individual resistances. R_total = R_1 + R_2 + R_3 R_total = 2 + 4 + 6 R_total = 12 Total resistance R_total = 12 ii) Calculate the current flowing in the circuit. Step 1: Use Ohm's Law, V = IR, where V is the total voltage and R is the total resistance. Rearrange for current I: I = V_totalR_total Step 2: Substitute the values. I = 24 V12 I = 2 A Current flowing in the circuit I = 2 A iii) Calculate the potential difference across each resistor. Step 1: The current is the same through all resistors in a series circuit (I = 2 A). Use Ohm's Law (V = IR) for each resistor. For the 2 resistor (R_1): V_1 = I × R_1 V_1 = (2 A) × (2 ) V_1 = 4 V Potential difference across 2 resistor V_1 = 4 V For the 4 resistor (R_2): V_2 = I × R_2 V_2 = (2 A) × (4 ) V_2 = 8 V Potential difference across 4 resistor V_2 = 8 V For the 6 resistor (R_3): V_3 = I × R_3 V_3 = (2 A) × (6 ) V_3 = 12 V Potential difference across 6 resistor V_3 = 12 V