Problem 1: Resistors of 2 , 4 , and 6 are connected in series, and a voltage of 24 V is applied across them.

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Here are the calculations for the given circuit: Problem 1: Resistors of 2 Ω, 4 Ω, and 6 Ω are connected in series, and a voltage of 24 V is applied across them. i) Calculate the total resistance. Step 1: For resistors connected in series, the total resistance Rtotal is the sum of the individual resistances. Rtotal = R₁ + R₂ + R₃; Rtotal = 2 Ω + 4 Ω + 6 Ω; Rtotal = 12 Ω; Total resistance Rtotal = 12 Ω ii) Calculate the current flowing in the circuit. Step 1: Use Ohm's Law, V = IR, where V is the total voltage and R is the total resistance. Rearrange for current I: I = Vtotal/Rtotal Step 2: Substitute the values. I = 24 V12 Ω; I = 2 A; Current flowing in the circuit I = 2 A iii) Calculate the potential difference across each resistor. Step 1: The current is the same through all resistors in a series circuit (I = 2 A). Use Ohm's Law (V = IR) for each resistor. For the 2 Ω resistor (R₁): V₁ = I × R₁; V₁ = (2 A) × (2 Ω); V₁ = 4 V; Potential difference across 2 Ω resistor V₁ = 4 V For the 4 Ω resistor (R₂): V₂ = I × R₂; V₂ = (2 A) × (4 Ω); V₂ = 8 V; Potential difference across 4 Ω resistor V₂ = 8 V For the 6 Ω resistor (R₃): V₃ = I × R₃; V₃ = (2 A) × (6 Ω); V₃ = 12 V; Potential difference across 6 Ω resistor V₃ = 12 V

Problem 1: Resistors of 2 , 4 , and 6 are connected in series, and a voltage of 24 V is applied across them.

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Step-by-step solution

Part i· 1 step

For resistors connected in series, the total resistance $R_{total}$ is the sum of the individual resistances.

Part ii· 2 steps
$\text{Current flowing in the circuit } I = 2 \text{ A}$

Use Ohm's Law, $V = IR$ , where $V$ is the total voltage and $R$ is the total resistance.

Substitute the values.

Part iii· 1 step
$\text{Potential difference across } 2 \Omega \text{ resistor } V_1 = 4 \text{ V}$

The current is the same through all resistors in a series circuit ( $I = 2 \text{ A}$ ).

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Problem 1: Resistors of 2 , 4 , and 6 are connected in series, and a voltage of 24 V is applied across them.

Answers

Step-by-step solution

Part i· 1 step

For resistors connected in series, the total resistance RtotalR_{total}Rtotal​ is the sum of the individual resistances.

Part ii· 2 stepsCurrent flowing in the circuit I=2 A\text{Current flowing in the circuit } I = 2 \text{ A}Current flowing in the circuit I=2 A

Use Ohm's Law, V=IRV = IRV=IR, where VVV is the total voltage and RRR is the total resistance.

Substitute the values.

Part iii· 1 stepPotential difference across 2Ω resistor V1=4 V\text{Potential difference across } 2 \Omega \text{ resistor } V_1 = 4 \text{ V}Potential difference across 2Ω resistor V1​=4 V

The current is the same through all resistors in a series circuit (I=2 AI = 2 \text{ A}I=2 A).

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Still stuck on this one?

More Physics Questions

For resistors connected in series, the total resistance $R_{total}$ is the sum of the individual resistances.

Part ii· 2 steps
$\text{Current flowing in the circuit } I = 2 \text{ A}$

Use Ohm's Law, $V = IR$ , where $V$ is the total voltage and $R$ is the total resistance.

Part iii· 1 step
$\text{Potential difference across } 2 \Omega \text{ resistor } V_1 = 4 \text{ V}$

The current is the same through all resistors in a series circuit ( $I = 2 \text{ A}$ ).